5 replies to this topic

[XxXGoD]

I am trying to get a number returned for how many instances of a certain processor there is..

$PCount = ProcessList("test.exe")

I need it in a numeric format so I can do the following:

If $PCount = $PCount + 1 Then
; Do stuff here
End If

Edited by XxXGoD, 22 February 2012 - 06:57 PM.

[BrewManNH]

Did you look at the help file for ProcessList? It returns an array, and in the arrays [0][0] position is the number of processes found that match.

The array returned is two-dimensional and is made up as follows:
$array[0][0] = Number of processes
$array[1][0] = 1st Process name
$array[1][1] = 1st Process ID (PID)

[JLogan3o13]

You should be able to do something like this:

$list = ProcessList()
$x = 0
For $i = 1 To $list[0][0]
  If $list[$i][0] = "notepad.exe" Then
   $x = $x + 1
  EndIf
Next
MsgBox(0, "", $x)
 

[BrewManNH]

Or you could do this:

$PCount = ProcessList("notepad.exe")
MsgBox(64, "Count", "Number of notepad processes found = " & $PCount[0][0])

[JLogan3o13]

Even better, BrewManNH I was going off his requirement to do

If $PCount = $PCount + 1 Then
; Do stuff here
End If

[XxXGoD]

Hey Guys,

You should be able to do something like this:

 $list = ProcessList() $x = 0 For $i = 1 To $list[0][0] If $list[$i][0] = "notepad.exe" Then $x = $x + 1 EndIf Next MsgBox(0, "", $x) 

Perfect, thank you I had to change how it works a little but it works flawlessly.

Or you could do this:

 $PCount = ProcessList("notepad.exe") MsgBox(64, "Count", "Number of notepad processes found = " & $PCount[0][0]) 

I was unable to do what I wanted using that however the other guys works perfect.

Thank you very much both of you

Edited by XxXGoD, 23 February 2012 - 01:14 PM.