5 replies to this topic

[kritya]

Hi,

I have string , which I want to split into strings of equal size(characters) lets say 4 or 5.


Did some searching. Found this

$aNumber = StringRegExp($string, "\d{4}", 3)

This only works on numbers and not on general string.

Please Help me.

Thanks

[Melba23]

kritya,

Just look for any character and not just digits:

#include <Array.au3>

$sString = "1234abcd5678ghij1234abcd5678ghij"

$aArray = StringRegExp($sString, ".{4}", 3)

_ArrayDisplay($aArray)

If you want to start learning more about SREs, then I recommend this site.

M23

[somdcomputerguy]

Take a look at StringLen, and it's related String functions.

[czardas]

#include <Array.au3>

Dim $aArray = _StringEqualSplit("abcdefghijklmnopqrstuvwxyz", 5)
_ArrayDisplay($aArray)

Func _StringEqualSplit($sString, $iNumChars)
    Return StringRegExp($sString, "(?s).{1," & $iNumChars & "}", 3)
EndFunc

Hmm I didn't read Melba's responce. It's very nearly the same - the only difference is that any odd number of remaining characters are added to the final element.

Edited by czardas, 28 April 2012 - 03:27 PM.

[kritya]

kritya,

Just look for any character and not just digits:

#include <Array.au3>

$sString = "1234abcd5678ghij1234abcd5678ghij"

$aArray = StringRegExp($sString, ".{4}", 3)

_ArrayDisplay($aArray)

If you want to start learning more about SREs, then I recommend this site.

M23

Yes , I know that.

I am not good with regex but yea I can search it but wasn't able to find on this

And well by using

StringMid()

I made that.
Thanks all.
Code :

#include <Array.au3>

$string="1 2 3 4 5 6 7 8 9 1011"
$len=StringLen($string)
MsgBox(0,"",$len)
$len=$len/4
Local $arr[$len+1]
MsgBox(0,"",$len)
For $i=0 To $len
   $arr[$i]=StringMid($string,$i*4+1,4)
Next
 _ArrayDisplay($arr)

Any Better way of doing this or any kind of problem in this that may be faced in BIG strings or is the best method ?

Thanks

Edited by kritya, 28 April 2012 - 03:33 PM.

[jchd]

The regexp should run rings around your loop (on large strings).