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Hi I'm trying to make a small script (windowless), when you run it there needs to appear a context-menu where the cursor is. So if you double-click on the script file it looks like the menu appears on the script icon.. is this easy to do? can't find an answer directly, wish i could post some code to begin with but I have no clue how to start this Can i use $hMenu = GUICtrlCreateContextMenu(-1) for this with no window? dll calls are welcome to if it's not possible the simple way Like always, thanks in advance! TheAutomator