namedrisk Posted September 16, 2009 Share Posted September 16, 2009 Hi, i was thinking on how to get a percent from this piece of code but i couldnt get it to the paper: $MobHP = PixelSearch(736,48,910,49,0x3F3830,3) ; 173 pixels of hp If Not @error Then ;If pixel has been found to $coord $MobHPvalue = 909 - $MobHP[0] EndIf So if you see the piece of code i will get X every time i find the image i want the image i am looking for is an Health Bar that goes down from the right to the left so the value i get from 909 - X is from 0 to 173 since 909 - 736 = 173. So my question is how could i make it a 99% to 1% as it substracts it self to 173 1 = 99% and 173 = 0% i could make it by checking if X is bigger then X_new and small then X_next and create % by hand but it would look so ugly that i would like to find a new better way of doing it thanks for any help in advance Link to comment Share on other sites More sharing options...
omikron48 Posted September 16, 2009 Share Posted September 16, 2009 '(173 - x) / 173'? Link to comment Share on other sites More sharing options...
namedrisk Posted September 16, 2009 Author Share Posted September 16, 2009 Thank you very much for the fast reply don't belive i didnt came to that ... (173 - $MobHPvalueX) / 173 * 100 just did the trick thanks a lot ... Link to comment Share on other sites More sharing options...
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