StringTrimRight giving weird results

[EndFunc]

I have a line of text and when I try to trim the right it gives weird results.

Example

$sPath = "C:\scripts\autoit\mypath\morescripts\file.exe"

When I do this

$nPath = StringTrimRight($sPath,StringInStr($sPath,"\",0, -1))

It returns something weird like C:\scripts\autoit\mypath\mores

Instead of C:\scripts\autoit\mypath\morescripts\

What am I doing wrong cause my brain must be fried right now.

Edited May 27, 2010 by EndFunc

[MrMitchell]

Your StringInStr is returning position of the rightmost "\" starting from the left side which is like the 37th character. So 37 characters are being trimmed from the right side of the string.

Add:

Something like this could work...

;
;
$nPath = StringTrimRight($sPath,StringLen($sPath) - StringInStr($sPath,"\",0, -1))
 ;
;

Edited May 27, 2010 by MrMitchell

[jchd]

Reread the definition of StringInStr output, then the definition of StringTrimRight second parameter.

Then realize that the result of the former can't be (in your case) used directly by the latter!

Edit: I was diverted and overtaken!

Simpler:

$nPath = StringLeft($sPath, StringInStr($sPath,"\",0, -1))

Edited May 27, 2010 by jchd

[Bowmore]

StringLeft will give the answer you are looking for.

$sPath = "C:\scripts\autoit\mypath\morescripts\file.exe"
$nPath = StringLeft($sPath,StringInStr($sPath,"\",0, -1))

Edited May 27, 2010 by Bowmore

[SmOke_N]

MrMitchell pointed out what you needed with StringTrimRight ... You could have used StringLeft to achieve the same results the way you originally had it though:

$nPath = StringLeft($sPath, StringInStr($sPath,"\",0, -1))

Edit:

As Bowmore showed

Edit2:

And as jchd presented in his edit

Edited May 27, 2010 by SmOke_N

[EndFunc]

Your StringInStr is returning position of the rightmost "\" starting from the left side which is like the 37th character. So 37 characters are being trimmed from the right side of the string.

Add:

Something like this could work...

;
;
$nPath = StringTrimRight($sPath,StringLen($sPath) - StringInStr($sPath,"\",0, -1))
 ;
;

Ahh,doh.. That makes sense. I guess I was confusing myself.

Thanks for the help and setting me straight.

[EndFunc]

MrMitchell pointed out what you needed with StringTrimRight ... You could have used StringLeft to achieve the same results the way you originally had it though:

$nPath = StringLeft($sPath, StringInStr($sPath,"\",0, -1))

Edit:

As Bowmore showed

Thanks SmOke_N, that is actually what I was trying to do because I had done it before but couldn't understand why it wasn't working. Wrong function. lol I should try and find my old scripts as reference.