niubbone Posted June 1, 2010 Share Posted June 1, 2010 (edited) Why this gives error? I don't get it. When declaring a for cycle the 1st variable MUST be in any case in the format $i=1? Take a look, the error is in the second for... expandcollapse popup#include <array.au3> $Multi=ColloquioDomande() _ArrayDisplay($Multi,"PORCO") Func ColloquioDomande() Local $Domande[5]=["doma","domb","domc","domd","dome"] Local $Risposte[20]=["a","b","c","d","a1","b1","c1","d1","a2","b2","c2","d2","a3","b3","c3","d3","a4","b4","c4","d4"] Local $DomandeDifferenti[4] Local $RisposteMischiate[16] Local $i=1 Local $r=4 For $z=1 To 4 Local $GiroDomande=Random(1,Ubound($Domande)-1,1) $DomandeDifferenti[$z-1]=$Domande[$GiroDomande] _ArrayDelete($Domande,$GiroDomande) Select Case $GiroDomande=0 Local $Risp1=$Risposte[0],$Risp2=$Risposte[1],$Risp3=$Risposte[2],$Risp4=$Risposte[3] Case $GiroDomande=1 Local $Risp1=$Risposte[4],$Risp2=$Risposte[5],$Risp3=$Risposte[6],$Risp4=$Risposte[7] Case $GiroDomande=2 Local $Risp1=$Risposte[8],$Risp2=$Risposte[9],$Risp3=$Risposte[10],$Risp4=$Risposte[11] Case $GiroDomande=3 Local $Risp1=$Risposte[12],$Risp2=$Risposte[13],$Risp3=$Risposte[14],$Risp4=$Risposte[15] Case $GiroDomande=4 Local $Risp1=$Risposte[16],$Risp2=$Risposte[17],$Risp3=$Risposte[18],$Risp4=$Risposte[19] EndSelect Local $RisposteInOrdine[4]=[$Risp1,$Risp2,$Risp3,$Risp4] For $i To $r Local $GiroRispInOrdine=Random(1,Ubound($RisposteInOrdine)-1,1) $RisposteMischiate[$i-1]=$RisposteInOrdine[$GiroRispInOrdine] _ArrayDelete($RisposteInOrdine,$GiroRispInOrdine) Next $i+=4 $r+=4 Next Local $MultiDomERisp[2][16]=[[$DomandeDifferenti[0],$DomandeDifferenti[1],$DomandeDifferenti[2],$DomandeDifferenti[3]], _ [$RisposteMischiate[0],$RisposteMischiate[1],$RisposteMischiate[2],$RisposteMischiate[3],$RisposteMischiate[4], _ $RisposteMischiate[5],$RisposteMischiate[6],$RisposteMischiate[7],$RisposteMischiate[8],$RisposteMischiate[9]]] Return $MultiDomERisp EndFunc Well, i solved it. You have to do For $k=$i to $r. Therefore you can't declare the 1st condition of a for loop from outer the loop directly. Edited June 1, 2010 by niubbone Link to comment Share on other sites More sharing options...
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