how to check if an input box is empty

[Phenom]

if $input1 == "" doesn't work.

[XRS]

Try to use if $input1 = '' , if $input1 = ' ' or if $input1 = " " .

Maybe one of them will work

[Zibit]

if $input = 0 is the correct answer ^^

[XRS]

But if we use that if it will wont check if the inputbox have the value 0 ?

[Phenom]

None of those work.

[Zibit]

test it out i was right... it works

$input = InputBox("", "", "")  
if $input = 0 then ConsoleWrite("its empty")

to check if its 0 you have to have it if $input = "0" not $input = 0

0 is considered as empty

[Zibit]

and btw phenom it works... your's works... tested it

if ur meaning gui input then do like this

$read_input = guictrlread($input)
if $read_input = 0

[zorphnog]

First of all, are you talking about an InputBox or a GuiCtrlCreateInput? If you are using InputBox, $input1 == "" will work. If you are using the GuiCtrlCreateInput method you will need to use GuiCtrlRead($input1) to get the contents of the input box.

In the future, provide as much detail as possible. Saying that something doesn't work does not really give us much information. Always provide the code you have tried so that we can assess the problem.

[Zibit]

yeah we were kinda confused here ^^

[Phenom]

Yeah, I was talking about the inputbox for the gui, GuiCtrlCreateInput.

[99ojo]

Hi,

as Zorphnog suggests:

$input1 = GuiCtrlCreateInput.......

If GuiCtrlRead($input1) = "" Then MsgBox (0,"Empty.....", "....Input detected!")

;-))

Stefan

Edited June 4, 2010 by 99ojo