scriptomator Posted July 13, 2010 Share Posted July 13, 2010 (edited) Hi. I have attempted to make autoit read all of the number to the right of a decimal point=================================================================12.(54969) only these are to be read$before = 12.54969******read all numbers after decimal and place in variable******(the part i can't do)$after = 54969=================================================================i don't know if this can be done when it is an integer.if not, can it be read this way if it is converted into a stringi hope that there is not some amazingly simple solution to this problem that will make me look stupid for not realizing it right awaythank you to all who help Edited July 13, 2010 by scriptomator Link to comment Share on other sites More sharing options...
BugFix Posted July 13, 2010 Share Posted July 13, 2010 (edited) Try this: $before = 12.54969 $after = $before - Int($before) $after *= 10^(StringLen($after)-2) ConsoleWrite($after & @CRLF) ; another way: $tmp = StringSplit($before, '.', 2) $after = $tmp[1] ConsoleWrite($after & @CRLF) Edited July 13, 2010 by BugFix Best Regards BugFix Link to comment Share on other sites More sharing options...
scriptomator Posted July 13, 2010 Author Share Posted July 13, 2010 Try this: $before = 12.54969 $after = $before - Int($before) $after *= 10^(StringLen($after)-2) ConsoleWrite($after & @CRLF) ; another way: $tmp = StringSplit($before, '.', 2) $after = $tmp[1] ConsoleWrite($after & @CRLF) thank you so much and i also did not expect to get a response so quickly Link to comment Share on other sites More sharing options...
Malkey Posted July 13, 2010 Share Posted July 13, 2010 Another way. Local $before = 12.54969 MsgBox(0,"Results",$before & " has " & StringRegExpReplace($before, "(\d*\.)", "") & " after the decimal point." & @CRLF) Link to comment Share on other sites More sharing options...
PsaltyDS Posted July 13, 2010 Share Posted July 13, 2010 Yet another version, for the RegExp challenged: Local $before = 12.54969 Local $after = StringMid($before, StringInStr($before, ".", 0, -1) + 1) MsgBox(64, "Results", $before & " has " & $after & " after the decimal point." & @CRLF) Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law Link to comment Share on other sites More sharing options...
AndyG Posted July 13, 2010 Share Posted July 13, 2010 $a=123.456789 $b=number(stringtrimleft(string($a),stringinstr(string($a),".",1))) ConsoleWrite('@@ Debug(' & @ScriptLineNumber & ') : $b = ' & $b & @crlf & '>Error code: ' & @error & @crlf) ;### Debug Console ;failed...^^....sometimes it is overtaken by the reality $a=123.456789 $b=number(stringtrimleft(string($a-int($a)),2)) ConsoleWrite('@@ Debug(' & @ScriptLineNumber & ') : $b = ' & $b & @crlf & '>Error code: ' & @error & @crlf) ;### Debug Console Link to comment Share on other sites More sharing options...
GEOSoft Posted July 13, 2010 Share Posted July 13, 2010 There are just so many ways to do this you could be at it all day. $a = 123.456789 $iOut = StringMid($a, StringInStr($a, ".") +1) George Question about decompiling code? Read the decompiling FAQ and don't bother posting the question in the forums.Be sure to read and follow the forum rules. -AKA the AutoIt Reading and Comprehension Skills test.*** The PCRE (Regular Expression) ToolKit for AutoIT - (Updated Oct 20, 2011 ver:3.0.1.13) - Please update your current version before filing any bug reports. The installer now includes both 32 and 64 bit versions. No change in version number. Visit my Blog .. currently not active but it will soon be resplendent with news and views. Also please remove any links you may have to my website. it is soon to be closed and replaced with something else. "Old age and treachery will always overcome youth and skill!" Link to comment Share on other sites More sharing options...
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