-deleted-

[Guest Plemdsan]

-deleted-

Edited January 4, 2020 by Plemdsan

[nekkutta]

you might want to read through this: PCRE Specs

also you might want you use capture brackets '()' to capture exactly what you want.

also in the directory "program files\autoit3\examples\helpfile" there is a file "StringRegExpGUI.au3" you can use that to test the regexp engine, the radio button options are (top to bottom) 0,1,3

[Realm]

Hello JBtje,

SRE can be a fickle thing, and I have found it to be one of the most difficult functions in AutoIt to learn and understand.

First, Your third example is a correct way to obtaining the result you want for the First example. Reason your third example is incorrect is your asking it to capture what is inside [], /r=Carriage Return or @CR, /n = linefeed or @LF, so your asking it to capture @CRLF. Reason for the first is your asking it to Capture everything but '.' repetitively '+', and any combinations of 'how' so your end result from $data would be 'how'. This example which is your third, is what you want.

$zz1 = StringRegExp( $data, '[\r\n.]+', 1)
MsgBox(0,"1",$zz1[0])

In your Second example, your asking it to capture '.' since there are no periods in your $data string, you will result with nothing. In order to capture just the first word, these to examples will do the trick:

$zz2a = StringRegExp( $data, '(.*?)' & @CRLF, 1)
$zz2b = StringRegExp( $data, '[^/r/n]+' & @CRLF, 1)
MsgBox(0,"2","First Example= " & $zz2a[0] & @CRLF _
            &"Second Example= " & $zz2b[0])

As for your third example, I explained what it does in my First example. I'm not sure exatly what your goal is here, but to take a guess, you want the sentence to be one line, and if I am correct, you could use:

$zz = StringRegExpReplace($data,@CRLF,' ')
msgbox(0, "3", $zz)

; if you need a linefeed at the end, then return as
$zz = StringRegExpReplace($data,@CRLF,' ') & @CRLF
MsgBox(0,"3",$zz)

I hope this helps.

Realm

Edited October 16, 2010 by Realm

[GEOSoft]

The first example actually returns

hello

world

how

For me

In the second the dot will be read as a litteral when used in square brackets by the way.

StringRegExp($data, "^\b\w+\b\v", 1) gets the first word.

I don't know why you would ever have to use an SRE to return everything ($data already holds it) but if that's what you want then

StringRegExp($data, "(?s)^.+$", 1) will do it.

Look in my signature for the PCRE Toolkit to test SREs and SRERs

[Guest Plemdsan]

-deleted-

Edited January 4, 2020 by Plemdsan

[Jos]

Why would u want a "." behave differently within square braces, than outside of it? That makes no sense to me.... how come its done this weird way?

From the helpfile:

Matching Characters

[ ... ] Match any character in the set. e.g. [aeiou] matches any lower-case vowel. A contiguous set can be defined using a dash between the starting and ending characters. e.g. [a-z] matches any lower case character. To include a dash (-) in a set, use it as the first or last character of the set. To include a closing bracket in a set, use it as the first character of the set. e.g. [][] will match either [ or ]. Note that special characters do not retain their special meanings inside a set, with the exception of \\, \^, \-,\[ and \] match the escaped character inside a set.

You will find the same in the official docs for PCRE.

[Guest Plemdsan]

-deleted-

Edited January 4, 2020 by Plemdsan

[GEOSoft]

You didn't post any of your actual code for us to analyze what seems to be happening here and without that we can't help you.

[Guest Plemdsan]

-deleted-

 

Edited January 4, 2020 by Plemdsan