Jump to content

datediff (months and years)


gcue
 Share

Recommended Posts

im trying to get the date difference in months and years

$months = _DateDiff('M', $start_date, $end_date)

$years = $months / 12

how do i figure out how many months there are when its .3 for instance??

Link to comment
Share on other sites

What is "its"? years or months?

Do you have an example with real dates to test?

Edited by water

My UDFs and Tutorials:

Spoiler

UDFs:
Active Directory (NEW 2022-02-19 - Version 1.6.1.0) - Download - General Help & Support - Example Scripts - Wiki
ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts
OutlookEX (2021-11-16 - Version 1.7.0.0) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download
Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki
PowerPoint (2021-08-31 - Version 1.5.0.0) - Download - General Help & Support - Example Scripts - Wiki
Task Scheduler (NEW 2022-07-28 - Version 1.6.0.1) - Download - General Help & Support - Wiki

Standard UDFs:
Excel - Example Scripts - Wiki
Word - Wiki

Tutorials:
ADO - Wiki
WebDriver - Wiki

 

Link to comment
Share on other sites

gcue,

If you need a Integer call for both years and months, you could do something like this:

$total_months = _DateDiff('M', $start_date, $end_date)

$years = Floor($total_months / 12)

$months = $total_months-($years*12)

Realm

Edit: Fixed an error I wrote in the code.

Edited by Realm

My Contributions: Unix Timestamp: Calculate Unix time, or seconds since Epoch, accounting for your local timezone and daylight savings time. RegEdit Jumper: A Small & Simple interface based on Yashied's Reg Jumper Function, for searching Hives in your registry. 

Link to comment
Share on other sites

hmm the result of these gives me 1 year and 11 months

$start_date = 2008-11-19 00:00:00

$end_date = 2010-11-02 00:00:00

thanks for your help realm!

water - sorry i wasnt clear. trying to get a more accurate change in datediff (showing # of years and months - to the nearest month). so like the dates shown above should be 2 years and 0 months?

Edited by gcue
Link to comment
Share on other sites

You only get full months and years so the result is correct!

Edited by water

My UDFs and Tutorials:

Spoiler

UDFs:
Active Directory (NEW 2022-02-19 - Version 1.6.1.0) - Download - General Help & Support - Example Scripts - Wiki
ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts
OutlookEX (2021-11-16 - Version 1.7.0.0) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download
Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki
PowerPoint (2021-08-31 - Version 1.5.0.0) - Download - General Help & Support - Example Scripts - Wiki
Task Scheduler (NEW 2022-07-28 - Version 1.6.0.1) - Download - General Help & Support - Wiki

Standard UDFs:
Excel - Example Scripts - Wiki
Word - Wiki

Tutorials:
ADO - Wiki
WebDriver - Wiki

 

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
 Share

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...