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yucatan
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Hello guys

today it wensday 17 november.

i wanne write a script.

that i get all date's of the week.

monday 15 november

truesday 16 november

wensday 17 november

etc

all days of this week with the date so 17 november .

is this possible.

how should i do this?

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Check out the date management in the help file. it has everything you need for dates/times

010101000110100001101001011100110010000001101001011100110010000

001101101011110010010000001110011011010010110011100100001

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This gives all the days of the current week starting with monday:

For $iIndex = 1 To 7
    $sdate = _DateAdd("d", (@WDAY*-1) + $iIndex + 1, @YEAR & "/" & @MON & "/" & @MDAY)
    ConsoleWrite($sdate & @CRLF)
Next

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_DateDayOfWeek(@WDAY)

will write out the current day of the week

@WDAY will give you a number 1-7, 1=Sunday, 2=Monday etc.

_DateAdd

_DateDiff

_NowCalcDate

Will return the date in format YYYY/MM/DD

_DateToMonth

Writes out name of the month 1-12, 1=January

That should be more than enough to get you going

010101000110100001101001011100110010000001101001011100110010000

001101101011110010010000001110011011010010110011100100001

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This gives all the days of the current week starting with monday:

For $iIndex = 1 To 7
    $sdate = _DateAdd("d", (@WDAY*-1) + $iIndex + 1, @YEAR & "/" & @MON & "/" & @MDAY)
    ConsoleWrite($sdate & @CRLF)
Next

Nice great men,

one more question.

is it possible to hang this on _WeekNumberISO

because what if i wanne do this but then i wanne use week 50 as info.

i wanne request all dates of week 50?

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_WeekNumberISO returns the week number.

I would start with the 1st of January, check for the target weeknumber and increment if necessary using _DateAdd.

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i'm sorry i dont fully understand ur post.

To my knowledge there is no function available that returns the start date (monday) of a given week number.

So I suggest to start with 2010/01/01. Use _WeekNumberISO to get the week number for this date and compare it to the desired week number (50 in your case).

If the week number has not reached the target week increment the date using _DateAdd.

Run this in a loop.

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To my knowledge there is no function available that returns the start date (monday) of a given week number.

So I suggest to start with 2010/01/01. Use _WeekNumberISO to get the week number for this date and compare it to the desired week number (50 in your case).

If the week number has not reached the target week increment the date using _DateAdd.

Run this in a loop.

do u have a sample code maby?

i know i can

#include <Date.au3>

$data = _WeekNumberISO("2011","6","14")
ConsoleWrite($data)

i know that i can calc the weeknumber when i have the date.

i should create a loop that i runs it with all dates.

put it in a array.

i only dont know what is the best way to do this in a loop.

Edited by yucatan
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do u have a sample code maby?

Unfortunately not.

But given the needed functions in my last post it shouldn't be too hard.

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Quick & Dirty:

Global $sStartdate = "2010/01/01"
Global $iTargetWeek = 50
While 1
    $aDate = StringSplit($sStartdate, "/")
    $iWeek = _WeekNumberISO($aDate[1], $aDate[2], $aDate[3])
    If $iWeek <> $iTargetWeek Then
        $sStartDate = _DateAdd("d", 1, $sStartDate)
    Else
        ExitLoop
    EndIf
WEnd
ConsoleWrite("Week " & $iTargetWeek & " starts on " & $sStartDate & @CRLF)

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I was attempting to do something like:

#include <Date.au3>

$i=1

$data = _WeekNumberISO("2010",String($i),"1")

ConsoleWrite("WeekISO="&$data&@CRLF)

Do

$i+=1

$data = _WeekNumberISO("2011",String($i),"1")

ConsoleWrite("WeekISO="&$data&@CRLF)

Until $data>=50

However, something with that function is not right because this is the result I got:

WeekISO=52

WeekISO=5

WeekISO=9

WeekISO=13

WeekISO=17

WeekISO=22

WeekISO=26

WeekISO=31

WeekISO=35

WeekISO=39

WeekISO=44

WeekISO=48

WeekISO=-1

WeekISO=-1

WeekISO=-1...........etc. etc. etc.

*edit*

I know I should have set it up as

#include <Date.au3>

$i=0

Do

$i+=1

$data = _WeekNumberISO("2011",String($i),"1")

ConsoleWrite("WeekISO="&$data&@CRLF)

Until $data>=50

but then it stops at month 1 day 1 with a value of 52...

Edited by kaotkbliss

010101000110100001101001011100110010000001101001011100110010000

001101101011110010010000001110011011010010110011100100001

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However, something with that function is not right because this is the result I got:

It depends on how you define "week number". Please check this.Or - even better - this. Edited by water

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It depends on how you define "week number". Please check this.Or - even better - this.

at this point i'm stuck at the point as kaotkbliss.

we still searching for a good way.

the sample u gived me works good.

but how can i discover the end date?

how can i let this loop for for more then one week number?

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That's confusing...

However, this will get the variable $data close to a desired week number

#include <Date.au3>

$input=InputBox("enter week number","")

$i=0

Do

$i+=1

$data = _WeekNumberISO("2011",String($i),"7")

ConsoleWrite("WeekISO="&$data&@CRLF)

Until $data>=Int($input)-7 And $data<=Int($input)+7

010101000110100001101001011100110010000001101001011100110010000

001101101011110010010000001110011011010010110011100100001

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at this point i'm stuck at the point as kaotkbliss.

we still searching for a good way.

the sample u gived me works good.

but how can i discover the end date?

how can i let this loop for for more then one week number?

Come on - given the code in my last post this is quite easy.

My code returns the first day in the week you specify.

Increment the date 6 times and you have all dates of the required week!

Edited by water

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Come on - given the code in my last post this is quite easy.

My code returns the first day in the week you specify.

Increment the date 6 times and you have all dates of the required week!

yeah that i understand.

but i need the start and end date of all weeks.

1 until 52.

if possible of different years.

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Something to think about:

2010/01/01 is in week 52 of 2009. What do you want to get as a start of this week?

If you have Outlook, check the calender to see when a week starts and ends.

Edited by water

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