[SOLVED] Syntax way: $a[$n]=StringLen($a2[$a3[$n]])

[Thlitmi]

$array[$number]=StringLen($array2[$array3[$number]])

Is not a valid syntax.

But I do not know how else I would solve this problem.....

I do not know under what name of "something" I should search help abou this problem...

Index of array2 is defined by values of array3 , how to do it ?

//edit:

And of-course, I work with this in loop, where $number is not static)

Edited December 5, 2010 by Thlitmi

[trancexx]

Your problem is very likely semantics since that's perfectly valid syntax.

[Thlitmi]

That should mean,that I have error somewhere else .. !

[Newb]

That should mean,that I have error somewhere else .. !

Post source for more help then.

[Thlitmi]

$number[x] is sometimes equal to number -1

Thats not good, because there is no array index number -1

I will try to filter it to see if it'll help.

[Zedna]

Maybe you are looking for UBound()

[Thlitmi]

After applying the fiter, it worked

So the error is, that one of my functions returned value that can not be used for array. It was like invisible error....

[sOLVED]

[Zedna]

[sPLVED]

[sOLVED]

[Thlitmi]

[sOLVED]

wow ! :-D