quick_sliver007 Posted June 10, 2005 Share Posted June 10, 2005 I was playing with arrays inside of arrays and I figure out how to get to the the array 1 down from the mother array so to speak. How do i get to the arrays farther down the line then 1 from the top most array. Here is the code I been playing with. expandcollapse popup#include <array.Au3> Dim $arraya[2] Dim $arrayb[2] Dim $arrayc[3] dim $arrayd[2] $arrayd[0] = "arrayd0" $arrayd[1] = "arrayd1" $arrayc[0] = "arrayc0" $arrayc[1] = "arrayc1" $arrayc[2] = $arrayd $arrayb[0] = "arrayb0" $arrayb[1] = "arrayb1" $arraya[0] = $arrayb $arraya[1] = $arrayc For $i = 0 to 1 MsgBox(0,"",$arrayb[$i]) Next For $i = 0 to 1 MsgBox(0,"",$arrayc[$i]) Next ;For $i = 0 to 1 ;MsgBox(0,"",$array[$i]) ;Next MsgBox(0,"",ubound($arraya[1])) _ArrayDisplay($arraya[1],"") _ArrayAdd($arraya[1],"new") _ArrayDisplay($arraya[1],"") _ArrayDelete($arraya[1],1) _ArrayDisplay($arraya[1],"") ;how do i get it to display the $arrayd from $arraya[1] ;in other words get to $arrayd though $arrayc though $arraya . Link to comment Share on other sites More sharing options...
jdickens Posted June 10, 2005 Share Posted June 10, 2005 (edited) This is not what you are asking perhaps, but something to consider: #include <array.Au3> Dim $MDRA [2] [2] [3] [2] $a = 1 $b = 2 $c = 3 $d = 4 $sp = " " Func InitMDRA() For $ai = 0 To UBound($MDRA, $a) - 1 For $bi = 0 To UBound($MDRA, $b) - 1 For $ci = 0 To UBound($MDRA, $c) - 1 For $di = 0 To UBound($MDRA, $d) - 1 $MDRA [$ai] [$bi] [$ci] [$di] = "Array Location " & _ "A" & $ai & $sp & _ "B" & $bi & $sp & _ "C" & $ci & $sp & _ "D" & $di Next Next Next Next EndFunc ;==>InitMDRA J Edited June 10, 2005 by jdickens If I am too verbose, just say so. You don't need to run on and on. Link to comment Share on other sites More sharing options...
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