C++ question!

[Maffe811]

Now, the reason i started with AutoIt was that it would hopefully lead me into the coding world and learn the basics before i took on C.

Now my friend that helped me get going, thinks im rappidly progressing with AutoIt and he suggested i should look at C++.

So im looking at some example scripts when i get to the script below.

And my question is, do AutoIt have an equvilant(?) to n-- ?

Because i have always used n=n-1.

// countdown using a for loop
#include <iostream>
using namespace std;
int main ()
{
  for (int n=10; n>0; n--) {
    cout << n << ", ";
  }
  cout << "FIRE!\n";
  return 0;
}

[jvanegmond]

The question is, why not:

for (int n=10; n>0; n-=1) {

Edited June 7, 2011 by Manadar

[Jos]

And my question is, do AutoIt have an equvilant(?) to n-- ?

Because i have always used n=n-1.

Closest thing in AutoIt3 is:

$n -= 1

[Mobius]

In the c source the n-- component of the for loop as you would expect is to decrement integer n by 1, within a for loop in AutoIt3 the facility of the increment / decrement instruction is handled by the optional STEP parameter, default c equivelent without the step parameter would be n++

AutoIt3 example

_Main()
;
FUNC _Main()
FOR $n = 10 TO 1 STEP -1
    ConsoleWrite($n &',')
NEXT
ConsoleWrite('FIRE!'& @LF)
RETURN 0
ENDFUNC

Edited June 7, 2011 by Mobius

[Maffe811]

The question is, why not:

for (int n=10; n>0; n-=1) {

Its not my script.

Its an example script.

Closest thing in AutoIt3 is:

$n -= 1

Okay, thats what i needed to know

I expect $n += 1 goes upwards ?

In the c source the n-- component of the for loop as you would expect is to decrement integer n by 1, within a for loop in AutoIt3 the facility of the increment / decrement instruction is handled by the optional STEP parameter, default c equivelent without the step parameter would be n++

AutoIt3 example

_Main()
;
FUNC _Main()
FOR $n = 10 TO 1 STEP -1
    ConsoleWrite($n &',')
NEXT
ConsoleWrite('FIRE!'& @LF)
RETURN 0
ENDFUNC

Okay, so now i have both the $n -= 1 and The Step parameter to use.

Thanks for clearing it up for me

[Mat]

The question is, why not:

for (int n=10; n>0; n-=1) {

and why not:

for (int n=10; n>0; n+=-1) {

They all compile the same in the end.

[AdmiralAlkex]

Okay, thats what i needed to know

I expect $n += 1 goes upwards ?

Sure does

There are some others too, see Helpfile > Language Reference > Operators

[Valik]

C++ source code is not called "script".

[Maffe811]

Should i just call it C++ code then ?

[ProgAndy]

Should i just call it C++ code then ?

That's right.

[Maffe811]

Ask for one thing, then you learn two things.

I love this forum.