Executables with the same name - WinSetTitle

[GordonFreeman]

Hi. I am a layman in autoit. My problem is this, I created a script to change the name of the window with thePID of the respective process. In the first run work fine, but then he always uses the same PID as the process name is the same. I know the error but not the solution. Can anyonehelp me?

ShellExecute("BLA.exe")

Sleep(3000)

$PID = ProcessExists("BLA.exe")

WinSetTitle("Blaaa Bla Bla","",$PID)

Exit

I want to make each window with its PID real and not only the first

Note: I can not change the name of the executable

happens the following problem:

BLA.EXE - REAL PID: 1234 - WINDOW NAME: 1234

the second time I open my program have:

BLA.EXE - REAL PID: 1234 - WINDOW NAME: 1234

BLA.EXE - REAL PID: 3131 - WINDOW NAME: 1234

i need so:

BLA.EXE - REAL PID: 1234 - WINDOW NAME: 1234

BLA.EXE - REAL PID: 3131 - WINDOW NAME: 3131

[Beege]

If your lanching an exe i would use Run() instead of shellexecute. Shellexecute is more for opening a file with its default application. Using Run() will return the pid without the need for ProcessExists(). Is that the whole script your running? If so, are you just running it twice to get the second bla.exe to launch?

[GordonFreeman]

If your lanching an exe i would use Run() instead of shellexecute. Shellexecute is more for opening a file with its default application. Using Run() will return the pid without the need for ProcessExists(). Is that the whole script your running? If so, are you just running it twice to get the second bla.exe to launch?

Thank you for your help. I reached my goal. perfect

ProcessExists and depedence of sleep removed, now is perfect, big ty man. See:

$PID = Run("BLA.exe")

WinWaitActive("Blaaa Bla Bla")

WinSetTitle("Blaaa Bla Bla","",$PID)

Exit