StringRegExpReplace - What am I missing? [Solved]

[icu]

Dear AutoIt Community,

I'm getting SQLite errors because of the single quote character in a string (').

I figured I could escape it out using a Func based on StringRegExpReplace however it doesn't work and I just don't see why. Here is my code:

Func SQLite_Regex (ByRef $string)
$value = StringRegExpReplace ($string, ".('+).", "''")
Return $value
EndFunc
 
$s_Test = "De L'isard's"
ConsoleWrite ("Before SQLite_Regex: " & $s_Test & @CRLF)
$s_Result = SQLite_Regex ($s_Test)
ConsoleWrite ("After SQLite_Regex: " & $s_Result & @CRLF)

I was pretty sure I escaped the single quotes with the double quotes enclosure.

Any and all help is greatly appreciated.

Kind regards,

icu

Edited September 24, 2011 by icu

[SmOke_N]

StringReplace would be faster:

StringReplace($string, "'", "''", 0, 1)

But... Your question:

StringRegExpReplace($string, "'", "''")

Edited September 24, 2011 by SmOke_N

[icu]

@ SmOke_N: Thanks!

[t0nZ]

Single quote character (') for Europeans (and not english speaking countries in general ) is a problem.

A lot of systems have words with accent (mark) , and with sqlite I have to cope with this situations.

For a long time I used this function :

Func apostrofo($letto)

$letto = StringRegExpReplace($letto, "(w)(')(w)", "1223") ; tra caratteri ;perla ; pearl
$letto = StringRegExpReplace($letto, "(w)(')(s)", "1223") ; carattere prima e dopo spazio carattere
$letto = StringRegExpReplace($letto, "(s)(')(w)", "1223") ; spazio e poi carattere
$letto = StringRegExpReplace($letto, "(s)(')(s)", "1223") ; spazio e poi spazio
$letto = StringRegExpReplace($letto, "(w)(')(Z)", "122") ; ultimo carattere è apostrofo
$letto = StringRegExpReplace($letto, "(A)(')(w)", "223") ; primo carattere è apostrofo
$letto = StringRegExpReplace($letto, "(s)(')(Z)", "122") ; ultimo carattere è apostrofo prima di spazio
$letto = StringRegExpReplace($letto, "(A)(')(s)", "223") ; primo carattere è apostrofo e dopo uno spazio
$letto = StringRegExpReplace($letto, "(w)(')(,)", "1223") ; carattere e poi virgola ;perla ; pearl , scoperto in tortora.au3
$letto = StringRegExpReplace($letto, "(,)(')(w)", "1223") ; virgola e poi carattere ;perla ; pearl , scoperto in tortora.au3
$letto = StringRegExpReplace($letto, "(w)(')(-)", "1223") ; carattere e poi - ;perla ; pearl , scoperto in tortora.au3
$letto = StringRegExpReplace($letto, "(w)(')(()", "1223") ; carattere e poi ( ;perla ; pearl , scoperto in tortora.au3

Return $letto
EndFunc   ;==>apostrofo

Until now, when I have problems with the last line (w)(')(()", "1223") where the (() don't work at all ... ?

But I found this thread and I think I was blind for not seeing a very simple and fast solution like that.

thankS !

So I don't use anymore my old function, but for the ()) in regular expression anyone has a solution ?

(sorry for the english...)

[jchd]

You're making your life more difficult that it should be!

Your (() should be (() : remember that ( is an active token in regexps.

Now, you should always escape each literal string in SQL statements using StringReplace($s, "'", "''"). The SQLite UDF doesn't offer data binding since it reveals much slower than SQLite_Exec in almost all practical uses.

[t0nZ]

You are right, now my function is modified in all my recent scripts and looks like:

Func apostrofo($letto)
$letto = StringReplace($letto, "'", "''", 0, 2)
Return $letto
EndFunc   ;==>apostrofo

Shortest and fastest !

Thanks.