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Check date before launch a file


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Please, can you show me the most efficent way to do this?

i want to launch a file, but only if the time of another file is > then 09:00 pm

In another words: if the time (last saved) of "fileA.xls" is > then 09:00pm then open "fileB.bat" otherwise wait 1 minute and restart the control until the time condition is verified.

Is possible to do this with autoit?

Thank you

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dont know if this is what you are looking for, have not tested but should do the trick.

$sFileToCheck = "FileA.xls"
$sFileToRun   = "FileB.bat"
 
While 1
    $aFileTime = FileGetTime($sFileToCheck)
    If IsArray($aFileTime) Then
        If $aFileTime[3] >= 9 Then
            Run($sFileToRun)
            ExitLoop
        Else
            Sleep(1000)
        EndIf
    EndIf
WEnd
Edited by DesireDenied
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dont know if this is what you are looking for, have not tested but should do the trick.

$sFileToCheck = "FileA.xls"
$sFileToRun   = "FileB.bat"
 
While 1
    $aFileTime = FileGetTime($sFileToCheck)
    If IsArray($aFileTime) Then
        If $aFileTime[3] >= 9 Then
            Run($sFileToRun)
            ExitLoop
        Else
            Sleep(1000)
        EndIf
    EndIf
WEnd

Thank you, works very well.

I have modified this code because i want add another check: i want that day, month and year of "FileA.xls" are equal to CURRENT day, month and year.

#include <Date.au3>
$sFileToCheck = "c:\AAA.xlsx"
$sFileToRun   = "c:\BBB.bat"
$tCur = _Date_Time_GetLocalTime()
$aCur = _Date_Time_FileTimeToArray($tCur)
 
While 1
    $aFileTime = FileGetTime($sFileToCheck)
    If IsArray($aFileTime) Then
       If $aFileTime[0] = $aCur[0] and $aFileTime[1] = $aCur[1] and $aFileTime[2] = $aCur[2] And $aFileTime[3] = 21 and $aFileTime[4] >= 41 Then
           Run($sFileToRun,"c:\")
           ExitLoop
       Else
           Sleep(10000)
       EndIf
    EndIf
WEnd

But day, month, year check doesn't work. Any ideas?

Thank you

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