default args c++

[JohnOne]

I'm having problems where autoit is crashing when calling a function in a dll file.

I am trying to give the function optional parameters.

From what I have read, it seems you can do it in much

the same way as autoit.

I have tried in a number of ways including

//prototype

//declaration

void add(int i = 0);

void add(int i = 0){

//stuff

}

void add(int i);

void add(int i = 0){

//stuff

}

void add(int);

void add(int i = 0){

//stuff

}

etc...

in all cases I get a crash if I do not pass it something.

Is there a specific way of achieving this for libraries, like overloading?

EDIT:

func is __stdcall if that makes any difference.

Edited February 21, 2012 by JohnOne

[Richard Robertson]

Optional parameters are not knowable at runtime. They are compile time constants ONLY. The reason they work in C++ when you include a header is because the header declares it so the compiler inserts it if you ignore it. If you are using a non-C++ language or not using the header which declares the default value, you must specify it like a normal parameter.

[JohnOne]

Yes the prototype is in a header file, and I'mm using VC++ VS2010.

AutoIt exits with -1073741819

Edited February 21, 2012 by JohnOne

[shanet]

JohnOne, it is my understanding that the prototype is where you declare defaults and the actual function does not have defaults. Eg:

int main(int a = 42, char b = 'a');  /* Prototype */

int main(int a, char <img src='http://www.autoitscript.com/forum/public/style_emoticons/<#EMO_DIR#>/cool.png' class='bbc_emoticon' alt='B)' /> {  /* Function */
  /* blah blah */
}

In my (little) experience, this is the correct way to do this.

[Shaggi]

Johnone, what you are trying to do is impossible. Optional parameters is only syntactic sugar resolved at compiletime as richard says. The function still expects the last parameter, hence you are corrupting the stack.

Normally, when you have default parameters, you set them to 0 - and the called function recognizes this as a default parameters. Eg:

void foo(int a, char * string) {
    if(!string) { // user called it like foo(5, NULL);
        //handle
    } else {
        //work with it
    }
    ...

}

Else you have to get into variadic functions, or passing an array of parameters and a count.

E: I guess you could overload the functions, afaik _stdcall gets exported as _[name]@[parameters_in_bytes]. However, you would still have to choose the right one.

JohnOne, it is my understanding that the prototype is where you declare defaults and the actual function does not have defaults. Eg:

int main(int a = 42, char b = 'a');  /* Prototype */

int main(int a, char <img src='http://www.autoitscript.com/forum/public/style_emoticons/<#EMO_DIR#>/cool.png' class='bbc_emoticon' alt='B)' /> {  /* Function */
  /* blah blah */
}

In my (little) experience, this is the correct way to do this.

You can also do it in the definition. Edited February 21, 2012 by Shaggi

[Richard Robertson]

Yes the prototype is in a header file, and I'mm using VC++ VS2010.

AutoIt exits with -1073741819

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[Beege]

That was good..

[jchd]

No, Jave (wild guess).

Good anyway!

[JohnOne]

Cheers for the info gentlebodes.