Path create.

[ileandros]

Hello,

Until now i was using this script to create a path

$sPath = StringReplace(@DesktopDir, "\AutoIt3.exe", "\")
$aFiles = _FileListToArray($sPath, "*.*", 1)
  For $i = 1 To $aFiles[0]
   GUICtrlSetData($List1, $aFiles[$i])
  Next

What can i do in case i want the Path to be something like this????

C:\Program Files\Java\jre6\bin

[somdcomputerguy]

$RestOfPath = "Javajre6bin"
ConsoleWrite(@ProgramsDir & $RestOfPath & @LF)

[ileandros]

Bruce

actually i just did it liek this and it works fine

$sPath = "C:Program FilesJavajre6bin"
$aFiles = _FileListToArray($sPath, "*.*", 1)

Thanks anyway

Edited April 9, 2012 by ileandros

[Opie]

ileandro, you will want to use @programsdir if you are distributing the script.

Not all program files directories are c;/program files/x

You have to take into account the Home Drive and 64 bit systems. So @programsdir is a sure fire way to find c:/program files

[ileandros]

Yes i know it but i dont want just to navigate the program files i want an other folder inside the program files. The way im doing it works fine. thanks