What's wrong with this?

[Khryus]

So, I made a function which has to break a line when it encounters a special character.

Func breakLine($string_to_break, $character_to_break)
    Local $stb=StringSplit($string_to_break, $character_to_break)
    Return $stb[1]&@CRLF&$stb[2]
EndFunc

And I am using it to modify a mask.

$desctable_mask="ACCID#@ACCNAME@#@@"
Local $sInfo[3]
$sInfo[0]="ID"
$sInfo[1]="DB"
$sInfo[2]="SC"
$patch=breakLine(StringReplace(StringReplace($desctable_mask, "ACCID", $sInfo[0]), "ACCNAME", $sInfo[1]), "@")

It actually breaks the line, however, this is what it should display on the output:

ID#
SC
#

And this is what it's actually displaying.

ID#
SC

How is that so?

What I am trying to do:

Break the line when a @ occurs

Replace "ACCID" with $sInfo[0]

Replace "ACCNAME" with $sInfo[1]

Display result in the output.

And no, ACCID and ACCNAME aren't "Account ID" and "Account Name", they're actually "Accessory ID" and "Accesory Name".

Thanks in advance

Edited April 18, 2012 by megablox

[BrewManNH]

Try this, your second "#" is in another element of the array. So you have to send that back as well in the Return statement.

$desctable_mask = "[email="ACCID#@ACCNAME"]ACCID#@ACCNAME[/email]@#@@"
Local $sInfo[3]
$sInfo[0] = "ID"
$sInfo[1] = "DB"
$sInfo[2] = "SC"
$patch = breakLine(StringReplace(StringReplace($desctable_mask, "ACCID", $sInfo[0]), "ACCNAME", $sInfo[2]), "@")
Func breakLine($string_to_break, $character_to_break)
    Local $stb = StringSplit($string_to_break, $character_to_break)
    Return $stb[1] & @CRLF & $stb[2] & @CRLF & $stb[3] ; I'm not sure if you need another @CRLF at the end of the Return line as well
EndFunc   ;==>breakLine

[Khryus]

Oh yeah, thanks ! That worked

By the way, would this automatically return all the items in the array?

Func breakLine($string_to_break, $character_to_break)
    Local $stb = StringSplit($string_to_break, $character_to_break)
    Local $mrg = ""
    For $i=1 To $stb[0] Step 1
        $mrg=$stb[$i]&@CRLF
    Next
    Return $mrg;$stb[1] & @CRLF & $stb[2] & @CRLF & $stb[3]
EndFunc   ;==>breakLine

Edited April 18, 2012 by megablox

[Khryus]

Woops

instead of

$mrg=$stb[$i]&@CRLF

I changed that line to

$mrg=$mrg&$stb[$i]&@CRLF

Then I tested it, but it a few more returns.

ID#
SC
#
<return here>
<return here>

Edited April 18, 2012 by megablox

[BrewManNH]

You're going to get the extra blank lines because the test string ends in "@@" and the string split will split there, which creates 2 empty elements.

[Khryus]

Oh yeah, that's right.Thank you