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AutoIt Login Form without MySQL


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Dear AutoIt users,

I've read the forum rules and I didn't find any topic like this...Sorry

Three days ago I've started a project in AutoIt to open account informations based on what user is and what he want to do. If you didn't understand, no problem, this is important:

I have a lot of troubles with MySQL and I was asking for some help. I tried everything...I know this script is wrong but take a look:

#include <ButtonConstants.au3>
#include <GUIConstantsEx.au3>
#include <WindowsConstants.au3>
$Form1 = GUICreate("Multiple GUI Managing", 215, 78, 192, 124)
$Button1 = GUICtrlCreateButton("Button", 24, 8, 137, 65, $WS_GROUP)
GUISetState(@SW_SHOW)

While 1
    $nMsg = GUIGetMsg()
    Switch $nMsg
        Case $GUI_EVENT_CLOSE
            Exit
         Case $Button1
            GUISetState(@SW_DISABLE, $Form1)
            SetGUI2()
            GUISetState(@SW_ENABLE, $Form1) 
     EndSwitch
WEnd

Func SetGUI2()
   $Form2 = GUICreate("Child window is still here", 377, 212, 192, 124)
   $Username = GUICtrlCreateInput("Username", 64, 72, 209, 21)
   $Password = GUICtrlCreateInput("Password", 64, 104, 209, 21)
   $Button2 = GUICtrlCreateButton("Button", 136, 136, 73, 33, $WS_GROUP)
   GUISetState(@SW_SHOW)

   While 1
      $nMsg = GUIGetMsg()
    Switch $nMsg
        Case $GUI_EVENT_CLOSE
            Exit
         Case $Button2
            GUIDelete($Form1)
            $ReadingUsername = GUICtrlRead($Username)
            $ReadingPassword = GUICtrlRead($Password)
            If $ReadingUsername = "user1" and $ReadingPassword = "password1" or $ReadingUsername = "user2" And $ReadingPassword = "password2" Then
               MsgBox(0,"TEST!", "Login test has been passed!")
            Else
               MsgBox(0,"TEST!", "Login test has not been passed!")
            EndIf
    EndSwitch
WEnd
EndFunc

Please help me fast,

-Armand ;)

Edited by ArmandCool
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Is this what you're after?

#include <ButtonConstants.au3>
#include <GUIConstantsEx.au3>
#include <WindowsConstants.au3>
$Form1 = GUICreate("Multiple GUI Managing", 215, 78, 192, 124)
$Button1 = GUICtrlCreateButton("Button", 24, 8, 137, 65, $WS_GROUP)
GUISetState(@SW_SHOW)
While 1
    $nMsg = GUIGetMsg()
    Switch $nMsg
        Case $GUI_EVENT_CLOSE
            Exit
         Case $Button1
            GUISetState(@SW_DISABLE, $Form1)
            SetGUI2()
            GUISetState(@SW_ENABLE, $Form1)
     EndSwitch
WEnd
Func SetGUI2()
   $Form2 = GUICreate("Child window is still here", 377, 212, 192, 124)
   $Username = GUICtrlCreateInput("Username", 64, 72, 209, 21)
   $Password = GUICtrlCreateInput("Password", 64, 104, 209, 21)
   $Button2 = GUICtrlCreateButton("Button", 136, 136, 73, 33, $WS_GROUP)
   GUISetState(@SW_SHOW)
   While 1
      $nMsg = GUIGetMsg()
    Switch $nMsg
        Case $GUI_EVENT_CLOSE
            Exit
         Case $Button2
            GUIDelete($Form1)
            $ReadingUsername = GUICtrlRead($Username)
            $ReadingPassword = GUICtrlRead($Password)
            If ($ReadingUsername = "user1" And $ReadingPassword = "password1") or ($ReadingUsername = "user2" And $ReadingPassword = "password2") Then
               MsgBox(0,"TEST!", "Login test has been passed!")
            Else
               MsgBox(0,"TEST!", "Login test has not been passed!")
            EndIf
    EndSwitch
WEnd
EndFunc

EDIT:

$ReadingUsername = "user1" ; accepts user1, User1, uSeR1 ... case insensitive

$ReadingUsername == "user1" ; only accepts exactly user1. case sensitive

Edited by footswitch
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I'm still getting the else function of the If...I mean I'm getting the Login test has not been passed! error in both accounts even if I compile the script... So, is there another way?

P.S.: I run Win XP x32 if it's important...

Edited by ArmandCool
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If I use footswitch's script and enter user1 and password1, or user2 and password2, I get login passed.

If I posted any code, assume that code was written using the latest release version unless stated otherwise. Also, if it doesn't work on XP I can't help with that because I don't have access to XP, and I'm not going to.
Give a programmer the correct code and he can do his work for a day. Teach a programmer to debug and he can do his work for a lifetime - by Chirag Gude
How to ask questions the smart way!

I hereby grant any person the right to use any code I post, that I am the original author of, on the autoitscript.com forums, unless I've specifically stated otherwise in the code or the thread post. If you do use my code all I ask, as a courtesy, is to make note of where you got it from.

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Use brackets in your if/then expression:

If ($ReadingUsername = "user1" and $ReadingPassword == "password1") or ($ReadingUsername = "user2" And $ReadingPassword == "password2") Then

Edit: ops, footswitch already provided same solution.

Br,

UEZ

Edited by UEZ

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