Math help

[Rutger83]

Hi everyone,

I am making a simple multiplayer turn based game for myself and my colleges. But I am stuck with some mathematic problems, maybe someone can help me, perhaps I should go to some math forum, who knows

The problem is the following: after a few survey questions I know my winning percentage vs a player, but I dont know how to calculate my percentage vs mutiply players.

for example:

My percentage vs player 1 is 70%

My percentage vs player 2 is 60%

My percentage vs player 3 is 65%

my winning percentage vs all 3 players is ???

can anyone guide me how to do this?

[nitekram]

65%

70+60+65/3 = 65

[IanN1990]

Simplest way of getting a percentage of something is.

Number / 100 * Percentage

or

Number * 0.Percentage

Edited December 15, 2012 by IanN1990

[IanN1990]

Not Completely understanding what your after but is this any good ?

$Amount = 100
$PlayerPercentage = 0.63 ;63%
$EnemyPercentage = 0.6 ;60%
$EnemyPercentage1 = 0.65 ;65%
$EnemyPercentage2 = 0.7 ;70%

$Player = $Amount*$PlayerPercentage

If $Amount*$EnemyPercentage > $Player Then
ConsoleWrite("Enemy1 wins")
ElseIf $Amount*$EnemyPercentage1 > $Player Then
ConsoleWrite("Enemy2 wins")
ElseIf $Amount*$EnemyPercentage2 > $Player Then
ConsoleWrite("Enemy3 wins")
Else
ConsoleWrite("Player wins")
EndIf

[nitekram]

I think OP is looking for something like this..

global $Player1 = 70, $Player2 = 60, $Player3 = 65
global $NumberOfPlayers = 3

msgbox(1, 'my winning percentage vs all ' & $NumberOfPlayers & ' players is', $Player1 + $Player2 + $Player3/$NumberOfPlayers & '%')

Edited December 15, 2012 by nitekram

[Rutger83]

Thanks for the suggestions but I dont think its the right thing. Let me try to clarlify it a bit.

I am comparing the hero vs an enemy thus I know that the hero has a 70% change of winning vs enemy 1, and so I also know that the hero has a 60% change of winning vs enemy 2.

But now I want to know my overall winning percentage with both enemies in the game. Which for my feeling should be lower then 60%. Vs enemy 2 I had a 60% but now I can also lose to enemy 1 so this should lower my overall changes of winning, right?

Something like this, might be more in the right direction...might... but its wrong... I dont really know how to solve it

global $enemy1 = 70, $enemy2 = 60, $enemy3 = 65

msgbox(1, 'my winning percentage vs all players is', ($enemy1 * ($enemy2/100) * ($enemy3/100)) & '%')

Edited December 15, 2012 by Rutger83

[nitekram]

If I were to beat player 1 70% of the time.

If I were to beat player 2 60% of the time.

If I were to beat player 3 65% of the time.

What is my winning percentage for against all 3 players? 65%

Unless, I am misunderstanding what you are looking for - that is the answer. You are going to loose 35% of the time on average.

Edited December 15, 2012 by nitekram

[Rutger83]

But I am facing the enemies simultaneous.

And I might be wrong here, but my feeling says that if I have a 60% of winning vs solely ememy 2, my winning percentage can not become higher when an extra enemy is in the game. Because there is another enemy to lose from, thus my percentage should become lower not higher.

[nitekram]

How about this, 65/3 = 21.67, does that seem better?

[jchd]

I guess "winning percentage" is not something rigourously defined here.

[bogQ]

it shud be calculated as recalculated procention on know procentage

so nothing is 100% everything is 99.9%

and calculation

$1 = 40
$2 = 10
$3 = 50
$4 = 60
$1_1 = $1-(0.1/(100-$1))
$2_2 = (($2/100)*$1_1)
$3_3 = (($3/100)*$2_2)
$4_4 = (($4/100)*$3_3)
MsgBox(0,'',$4_4)

so on 70% 60% 65% = around 27.2987% to survive

$1 = 70
$2 = 60
$3 = 65
$1_1 = $1-(0.1/(100-$1))
$2_2 = (($2/100)*$1_1)
$3_3 = (($3/100)*$2_2)
MsgBox(0,'',$3_3)

Edit: if i fliped calcylation (messed up maybe) it shud be

$1_1 = $1-(0.1/(100-$1))
$2_2 = (($1_1/100)*$2)
$3_3 = (($2_2/100)*$3)
$4_4 = (($3_3/100)*$4)
;vs
$1_1 = $1-(0.1/(100-$1))
$2_2 = (($2/100)*$1_1)
$3_3 = (($3/100)*$2_2)
$4_4 = (($4/100)*$3_3)

but my head hurts now from math and hell if i can see whats the correct one from 2 of them or are the 2 of them identical

Edited December 15, 2012 by bogQ