StringRegExpReplace on HTML not working

[detected]

Hi, I'm trying to get a part of the html source using regex.

StringRegExpReplace($Body, '^.*?<table id="content">(.*?)</table>.*$', '$1')

However, I get displayed the full html source as output... How to get $1?

[jchd]

Are you assigning the output to some variable ?

[JonBMN]

Any chance you could provide a snippet of your HTML code so that we can make sure your matching the string to check and the regexp correctly?

Edited April 17, 2013 by JonBMN

[Nessie]

You have to assign a variable to StringRegExpReplace

$sSource = '<table id="content">Nessie the monster</table>'
$sRegex = StringRegExpReplace($sSource, '^.*?<table id="content">(.*?)</table>.*$', '$1')
MsgBox(0, "Test", $sRegex)

Hi!

[detected]

You have to assign a variable to StringRegExpReplace

$sSource = '<table id="content">Nessie the monster</table>'
$sRegex = StringRegExpReplace($sSource, '^.*?<table id="content">(.*?)</table>.*$', '$1')
MsgBox(0, "Test", $sRegex)

Hi!

Ok I found the problem

This gives the same problem:

$sSource = '<table id="content">' & @CRLF & 'Nessie the monster</table>'
$sRegex = StringRegExpReplace($sSource, '^.*?<table id="content">(.*?)</table>.*$', '$1')
MsgBox(0, "Test", $sRegex)

I did a StringReplace on @CRLF, @CR and @LF and now it's working

[Nessie]

Or you can use the Matching Characters s to match:

Match any whitespace character: Chr(9) through Chr(13) which are Horizontal Tab, Line Feed, Vertical Tab, Form Feed, and Carriage Return, and the standard space ( Chr(32) ).

Hi!

[Malkey]

Continuing with Nessie's advice about s.

This example does not capture leading or trailing vertical or horizontal white spaces if they exist.

$sSource = '<table id="content">' & @CRLF & 'Nessie the monster</table>'
$sRegex = StringRegExpReplace($sSource, '^.*?<table id="content">\s*(.*?)\s*</table>.*$', '$1')
MsgBox(0, "Test", $sRegex)