Get a part outside a html file.

[Jack023]

Hey all,

I'm trying to get a part outside a html file :

I tried stringregexp but i don't get it, maybe easier ways?

Here is the code:

$url = "http://www.mysite.com/"

$oHTTP = ObjCreate("winhttp.winhttprequest.5.1")
; or :
; $oHTTP = ObjCreate("Microsoft.XMLHTTP")
$oHTTP.Open("GET", $url, 0)
$oHTTP.Send()
$txt = $oHTTP.Responsetext
$oHTTP = 0
$return = StringRegExp($txt, 'cols=60 wrap>(.*?)<textarea><form')
;~ MsgBox(0, "" , $txt)
MsgBox(0, "", $return)

It's something diffrent then my other thread and has nothing to do with it

Just a little note.

[karlkar]

Hello.

It would be easier if you could paste some html code - the part you want to extract the data from.

And please write what this code shows in msgbox.

Edited December 6, 2013 by karlkar

[Jack023]

It's showing the html code of the page.

</p>D S Technical Solutions A Plus Core Test Pro 3.3f14<br><br><textarea rows=8 cols=59>s/n: 12022002
s/n: 12022002</textarea><br><form action="/abuse.php" method="post" target="_blank"><input type="hidden" name="id" value="18851777"><input type="hidden" name="serialname" value="D S Technical Solutions A Plus Core Test Pro 3.3f14"><input type="submit" name="send" value="Send Abuse"></form><BR><BR><BR>
<center>Copyright Serials.BE c 2006, All rights reserved.</center>

Like as a example, i want the things between cols=59?s/n: and </textarea>

[karlkar]

Ok. You can try doing as you have tried, but with a little change: 

$return = StringRegExp($txt, 'cols=\d+>(.*?)</textarea>', 1)
MsgBox(0, "", $return[0])

StringRegExp without second parameter returns only 0 or 1 if it found text that match regular expression. Second parameter set to 1 makes it return Array of matches. You can read about it in docs.

You can also use different regexp:

<textarea.*>(.*?)</textarea>

Edited December 6, 2013 by karlkar

[Jack023]

works thanks