[Solved] Failing FileCopy creates hidden file

[Simpel]

Hi,

I'm using following code:

Global $FileName = "test.log"
Global $copyPath = "H:\Temp\Test\Log\"

FileCopy(@ScriptDir & "\" & $FileName,$copyPath)

If @error Then
    _DebugOut("Copy failed: " & $copyPath)
Else

    _DebugOut("Copied to: " & $copyPath)
EndIf

If folder "Log" is not existing then FileCopy creates a hidden file "Log" at "H:TempTest" with 1KB. 

Second I'll get the message in my debug file "Copied to: H:TempTestLog". But it's not true.

Any suggestions?

I tried an asterisk at the end of my $copyPath as it is suggested >here.

FileCopy(@ScriptDir & "\" & $FileName,$copyPath & "*")

Now there will be no hidden file but @error leads always to "Copied to: H:TempTestLog".

What's wrong?

Regards Simpel

Edited September 25, 2015 by Simpel
solved

[JLogan3o13]

Per the help file:

The destination directory must already exist, except using with flag value $FC_CREATEPATH (8).
For instance the combined flag $FC_OVERWRITE (1) + $FC_CREATEPATH (8) overwrites the target file and pre-checks for the destination directory structure and if it doesn't exist creates it automatically.

[Simpel]

Thanks.

I know. But it shouldn't try to create that folder.

So I decided to take the default, what is '0' or left blank.

It's not a solution for me.

Simpel

[Simpel]

Found out myself:

$msg = FileCopy(@ScriptDir & "\" & $FileName,$copyPath & "*")

If $msg = "1" Then
    _DebugOut("Copied to: " & $copyPath)
Else
    _DebugOut("Copy failed: " & $copyPath)
EndIf

Now no hidden file is created while failing and the debug messages will be correct.

Regards Simpel

P.S. Caution: the $copyPath has to end with a "".