Regex pattern

[AutID]

Hello,

I have some random paths and i want to get the file at the end of the path. The paths look like this: C:UsersrandomDesktoprandom1random1 updateupdated123whaeverbinyesDirectoryrandomSong.mp3

Which is the pattern to get only this; randomSong.mp3?  Or even better this: randomSong.

Sorry but i am really bad at regex.

 

Edited March 28, 2015 by AutID

[iamtheky]

$sString = "C:\Users\random\Desktop\random1\random1 update\updated\123\whaever\bin\yes\Directory\randomSong.mp3"

$aString = stringsplit($sString , "\")
msgbox(0, '' , stringtrimright($aString[$aString[0]] , 4))

or

$sString = "C:\Users\random\Desktop\random1\random1 update\updated\123\whaever\bin\yes\Directory\randomSong.mp3"

msgbox(0, '' , stringregexp($sString , ".*\\(.+)\.mp3" , 3)[0])

Edited March 28, 2015 by boththose

[AutID]

I was thinking about a stringsplit and a for loop to uboun the array and check for the .mp3 at the end and get the result but that's a lot of trouble for nothing. I like your regex. Thanks