rename the first letters of a file

[Eiyu]

Hello,
I will need to rename the first letters of all the files contained in a folder.
example:
My folder contains the following files:
"D:\Manual_20150620013430.txt"
"D:\Manual_20150620014428.txt"
"D:\Manual_20150620014604.txt"
... After "_" numbers are never identical

I want it to be like this after running the script:
"D:\Alarm_20150620013430.txt"
"D:\Alarm_20150620014428.txt"
"D:\Alarm_20150620014604.txt"

I found several methods, copy and paste with another name, move with another name and other ...
I'm bad, or not smart enough XD
Thank you in advance

 

Edited June 19, 2015 by Eiyu

[jvds]

maybe rename with the DOS 'ren a.txt b.txt'
or with

run(@ComSpec&' /C '&@ScriptDir&'/ren a.txt b.txt')

 

[BrewManNH]

If all the file names start with Manual_ you can use the DOS ren command to do it very easily.

Run(@ComSpec & " /c ren D:\Manual_*.txt Alarm_*.txt", "", @SW_HIDE)

This command will rename any file that starts with the word Manual followed by an underscore, and change the word Manual to Alarm. It will not show a window when doing it.

[Eiyu]

Thank you it's almost this:
This is what it does:

D:\Manual_20150620110854.txt

-> D:\Alarm__20150620110854.txt

There are two "_"  :-S

Thank you

[Rockerfeller]

You could try this then. Run(@ComSpec & " /c ren D:\Manual*.txt Alarm*.txt", "", @SW_HIDE) I also seen a filerename function in example scripts or wiki.