military time convert or calc

[abdulrahmanok]

military time for example :

when normal time : 10 Am  military time : 1000

when normal time : 7:30 Am  military time : 0730

what i want is there is code to convert military to normal  time ? because i want to calculate the difference between time

for normal time it's easy 10 Am - 7.5 Am = 2.5 Hours But in military Time its very difficult 1000-0730= ???

[SorryButImaNewbie]

Maybe break it in two (10 and 00, do it with the other) and do calculations that way?

(this way you dont really need to convert it back to normal)

Edited October 13, 2016 by SorryButImaNewbie

[Muhammad_Awais_Sharif]

May be this help you  
 

Local $firstTime = '1000';
Local $secondTime = '0730';


MsgBox(0,"1000 to 10:00",miltToNormal($firstTime))
MsgBox(0,"0730 to 07:30",miltToNormal($secondTime))

Func miltToNormal($time)
    return StringLeft($time,2) & ":" & StringRight($time,2)
EndFunc

 

[iamtheky]

If you just want math, then mil time is easier in my opinion

$time1 = "1145"
$time2 = "0730"

msgbox(0, '' , ((stringleft($time1 , 2) + stringright($time1 , 2) / 60)) - ((stringleft($time2 , 2) + stringright($time2 , 2) / 60)))

 

[abdulrahmanok]

5 minutes ago, Muhammad_Awais_Sharif said:

May be this help you  
 

Local $firstTime = '1000';
Local $secondTime = '0730';


MsgBox(0,"1000 to 10:00",miltToNormal($firstTime))
MsgBox(0,"0730 to 07:30",miltToNormal($secondTime))

Func miltToNormal($time)
    return StringLeft($time,2) & ":" & StringRight($time,2)
EndFunc

 

Ty Very much for super fast Response

Actually its converted but i failed to get Result between first time - second time

 

Local $firstTime = '1000';
Local $secondTime = '0730';
MsgBox(0,"1000 to 10:00",miltToNormal($firstTime))
MsgBox(0,"0730 to 07:30",miltToNormal($secondTime))

Func miltToNormal($time)
    return StringLeft($time,2) & ":" & StringRight($time,2)
EndFunc
MsgBox(0,"Re",$firstTime-$secondtime)

It gives me 270 whet it must be 230 ( 2 hours and 30 min ) .

[SorryButImaNewbie]

yeah you need to account for different possibilities (if 00 = 60 and others, I would think about it but dont have time )

 

good luck anyway

[iamtheky]

we are done at post #4, right? 

[orbs]

AutoIt it shipped with a UDF that handles time computations. first you must convert your military time to a calculable format, then diff the times and present in hours, like this:

#include <Date.au3>

Global $iTimeDiff = _DateDiff('n', _TimeConvert_MilitaryToCalc('0730'), _TimeConvert_MilitaryToCalc('1000')) / 60
MsgBox(0, '', $iTimeDiff)

Func _TimeConvert_MilitaryToCalc($sTime)
    Return @YEAR & '/' & @MON & '/' & @MDAY & ' ' & StringLeft($sTime, 2) & ':' & StringRight($sTime, 2) & ':' & '00'
EndFunc   ;==>_TimeConvert_MilitaryToCalc

look at the help for _DateDiff() and see why you need to convert the military time to calculable.

Edited October 13, 2016 by orbs

[kylomas]

Check out _datediff in the help file...

[abdulrahmanok]

15 minutes ago, iamtheky said:

If you just want math, then mil time is easier in my opinion

$time1 = "1145"
$time2 = "0730"

msgbox(0, '' , ((stringleft($time1 , 2) + stringright($time1 , 2) / 60)) - ((stringleft($time2 , 2) + stringright($time2 , 2) / 60)))

 

Ty very much It's worked like i want

sorry I didn't see your comment before Ty all

Solved .
Edit : You are Math genius

Edited October 13, 2016 by abdulrahmanok

[iamtheky]

no, you should legitimately use the UDF as recommended later, that way your code is portable when future you needs to reuse the snippet.  Do it the right way, for future you!

But its always fun to roll your own to make sure you understand what is going on.

[AdamUL]

Have a look at Melba23's Date_Time_Convert UDF.  

Here is an example using the UDF.  

#include <Date.au3>
#include <DTC.au3>

Global $sTime1 = "7:30 AM"
Global $sTime2 = "10:00 AM"

;Convert to Mil time.
Global $sMilTime1 = _Date_Time_Convert($sTime1, "h:mm TT", "HHmm")
Global $sMilTime2 = _Date_Time_Convert($sTime2, "h:mm TT", "HHmm")
ConsoleWrite("Mil Time" & @CRLF & $sMilTime1 & @CRLF & $sMilTime2 & @CRLF & @CRLF)

;Convert to 12 hr time.
Global $s12HrTime1 = _Date_Time_Convert($sMilTime1, "HHmm", "h:mm TT")
Global $s12HrTime2 = _Date_Time_Convert($sMilTime2, "HHmm", "h:mm TT")
ConsoleWrite("12 Hr Time" & @CRLF & $s12HrTime1 & @CRLF & $s12HrTime2 & @CRLF & @CRLF)

;Convert to calculable time.
Global $sCalcTime1 = _Date_Time_Convert($sTime1, "h:mm TT", "HH:mm")
Global $sCalcTime2 = _Date_Time_Convert($sTime2, "h:mm TT", "HH:mm")
ConsoleWrite("Calc Format Time" & @CRLF & $sCalcTime1 & @CRLF & $sCalcTime2 & @CRLF & @CRLF)

;Get today's date.
Global $sToday = _NowCalcDate()

;Calculate the difference between the two times.
Global $sTimeDiff = _DateDiff("n", $sToday & " " & $sCalcTime1, $sToday & " " & $sCalcTime2) / 60
ConsoleWrite("Time difference between " & $sTime1 & " and " & $sTime2 &  ": " & $sTimeDiff & " Hr" & ($sTimeDiff > 1 ? "s" : "") & @CRLF & @CRLF)

 

Adam

 

Edited October 13, 2016 by AdamUL

[jchd]

Just a sidenote: "normal time" like 00:00 AM is it "normal time" like 00:00 PM? Same issue -but more ambiguously- arises with 12:00 AM vs. PM where what that means depends on whom you're talking to and the convention each end is using.

"Normal" in this thread just means "like ambiguous US time" or am I misunderstanding something?

I'd say "normal time" is 24h explicit time.
$0.02

[iamtheky]

they are both normal, they are the only times that occur simultaneously.  Ambiguity would infer that they were different things (or that if misunderstood could lead to a wrong conclusion) rather than just different names for the same thing. (my attempt at the most ambiguous answer ever may have failed and the humor lost, but at least i tried).

Edited October 13, 2016 by iamtheky

[kylomas]

Consider this, the op has stated that he wants to calculate the difference in time (duration). 

Using this code yields an ambiguous if not erroneous result...

$time1 = "0800"
$time2 = "0700"

msgbox(0, '' , ((stringleft($time1 , 2) + stringright($time1 , 2) / 60)) - ((stringleft($time2 , 2) + stringright($time2 , 2) / 60)))

Because $time2 is smaller than $time1 it could be inferred that a date boundary has been crossed, hence the ambiguity/error.

Conclusion:

Better to use the supplied UDF with complete date/times supplied by the user.

My $.02

[jchd]

Are you betting your life on that?

Look at the table mid-page of https://en.wikipedia.org/wiki/12-hour_clock under the heading "Confusion at noon and midnight".

I'd call that table fairly confusing about the vertues of 12-hour notationS.

[abdulrahmanok]

@iamtheky

@AdamUL

@kylomas

@jchd

Thank You All for Your Suggestions I will working on it but later because I have to Complete Some project now

 

 

 

[abdulrahmanok]

10 hours ago, iamtheky said:

we are done at post #4, right? 

Yes ,Thank You very much .