Naveen_Naveen Posted June 8, 2017 Share Posted June 8, 2017 Hola autoit Users. I am coming back here since i am in need of help once again. i have a file which has the release number of that particular version. Using stringmid, I am able to retrieve the version number but I always retrive only 5 characters from the 25th position. But the release number is enclosed within quotes. What would be ideal is to navigate to the line (which i have done) and then take the string that is within the quotes . Is this in anyway possible ?? Regards, Naveen_NaveeN Link to comment Share on other sites More sharing options...
mikell Posted June 8, 2017 Share Posted June 8, 2017 This could work $res = StringRegExpReplace($txt, '(?s).*?"([^"]+).*', "$1") If not you might post the file Link to comment Share on other sites More sharing options...
iamtheky Posted June 8, 2017 Share Posted June 8, 2017 if its the only thing in double quotes on the line, this may succeed: $str= 'This line has a version number "9.51.6.1a" and it is in those quotes' msgbox(0 , "" , stringmid($str , StringInStr($str , '"' , 1) + 1 , (StringInStr($str , '"' , 0 , -1) - 1) - StringInStr($str , '"' , 0 , 1))) ,-. .--. ________ .-. .-. ,---. ,-. .-. .-. .-. |(| / /\ \ |\ /| |__ __||| | | || .-' | |/ / \ \_/ )/ (_) / /__\ \ |(\ / | )| | | `-' | | `-. | | / __ \ (_) | | | __ | (_)\/ | (_) | | .-. | | .-' | | \ |__| ) ( | | | | |)| | \ / | | | | | |)| | `--. | |) \ | | `-' |_| (_) | |\/| | `-' /( (_)/( __.' |((_)-' /(_| '-' '-' (__) (__) (_) (__) Link to comment Share on other sites More sharing options...
mikell Posted June 8, 2017 Share Posted June 8, 2017 7 minutes ago, iamtheky said: this may succeed I was sure that this was about to come iamtheky 1 Link to comment Share on other sites More sharing options...
Naveen_Naveen Posted June 12, 2017 Author Share Posted June 12, 2017 This is awesome !!!!! just what i wanted !!! you guys are just amazing Link to comment Share on other sites More sharing options...
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