Get current script path when is included from another

[omarisai]

Hello,

I cannot find how to get the path of the current running script when is included from another file, I am always getting the path of the caller script:

script1.au3

#include "folder\script2.au3"

ConsoleWrite("From script1:" & @CRLF)
ConsoleWrite("  @ScriptDir = " & @ScriptDir & @CRLF)
ConsoleWrite("  @WorkingDir = " & @WorkingDir & @CRLF)
ConsoleWrite("  @ScriptFullPath = " & @ScriptFullPath & @CRLF)

ConsoleWrite(@CRLF)

FromScript2()

Exit

script2.au3

#include-once

Local Const $ScriptDir = @ScriptDir
Local Const $WorkingDir = @WorkingDir
Local Const $ScriptFullPath = @ScriptFullPath

Func FromScript2()
   ConsoleWrite("From script2:" & @CRLF)
   ConsoleWrite("  @ScriptDir = " & @ScriptDir & @CRLF)
   ConsoleWrite("  @WorkingDir = " & @WorkingDir & @CRLF)
   ConsoleWrite("  @ScriptFullPath = " & @ScriptFullPath & @CRLF)

   ConsoleWrite(@CRLF)

   ConsoleWrite("  $ScriptDir = " & $ScriptDir & @CRLF)
   ConsoleWrite("  $WorkingDir = " & $WorkingDir & @CRLF)
   ConsoleWrite("  $ScriptFullPath = " & $ScriptFullPath & @CRLF)
EndFunc

Output:

From script1:
  @ScriptDir = C:\test_suite\autoit
  @WorkingDir = C:\test_suite\autoit
  @ScriptFullPath = C:\test_suite\autoit\script1.au3

From script2:
  @ScriptDir = C:\test_suite\autoit
  @WorkingDir = C:\test_suite\autoit
  @ScriptFullPath = C:\test_suite\autoit\script1.au3

  $ScriptDir = C:\test_suite\autoit
  $WorkingDir = C:\test_suite\autoit
  $ScriptFullPath = C:\test_suite\autoit\script1.au3

What I am looking for:

From script1:
  $ScriptDir = C:\test_suite\autoit

From script2:
  $ScriptDir = C:\test_suite\autoit\folder

 

Thanks in advance!

[jchd]

#include just concatenates source files. Hence the final script source is only one solid block without mention of who's who, so you can't know at runtime which source file the current excuting line belongs to.