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StringFormat, to one decimal place, unless there is a 0 after the decimal point


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Go to solution Solved by abberration,

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Hello everyone,
I have a probably simple question but it's driving me crazy.

I need to format a number to one decimal place, unless there is a 0 after the decimal point, in which case I need a number without a decimal point.


Have a number 
10.5 ->  010.5

;////////////////////////////////
;// Decimal precision
;////////////////////////////////
$double = 10.5

$fDouble = StringFormat("%05.1f", $double)
ConsoleWrite("Decimal precision: " & $fDouble & @CRLF)

That's ok.

But for  10.0 I want 00010 and got 010.0

 

;////////////////////////////////
;// Decimal precision
;////////////////////////////////
$double = 10.0

$fDouble = StringFormat("%05.1f", $double)
ConsoleWrite("Decimal precision: " & $fDouble & @CRLF)

 

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Is there more elegant solution? 

;////////////////////////////////
;// Decimal precision
;////////////////////////////////
$double = 10.5

IF IsFloat ($double) Then 
    $fDouble = StringFormat("%05.1f", $double)
    
    ConsoleWrite('@@ Debug(' & @ScriptLineNumber & ') : $fDouble = ' & $fDouble & @crlf & '>Error code: ' & @error & @crlf) ;### Debug Console
    
Else 
    $fDouble = StringFormat("%05i", $double)

    ConsoleWrite('@@ Debug(' & @ScriptLineNumber & ') : $fDouble = ' & $fDouble & @crlf & '>Error code: ' & @error & @crlf) ;### Debug Console
    
EndIf

 

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  • Solution
Local $double = 10.5, $fDouble
$fDouble = StringFormat(IsFloat ($double)?"%05.1f":"%05i", $double)
ConsoleWrite('@@ Debug(' & @ScriptLineNumber & ') : $fDouble = ' & $fDouble & @crlf & '>Error code: ' & @error & @crlf) ;### Debug Console

 

Ternary operators

Edited by abberration
added link to ternary operators
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Local $aValues = [10.5, 0.0, -1.0, -3.001, 5.00000001]

For $n In $aValues
    ConsoleWrite(StringFormat((IsInt($n) ? "%05i\n" : "%05.1f\n"), $n))
Next

Sorry for that, I was typing my answer but got diverted elsewhere while @abberration posted.

Edited by jchd

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