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Input Box Value Into Another Input Box - Im New Be Gentle!


markj
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Hi

i have a gui with an input box. i want the value of this input box to be the default value of another input box but it wont let me :mellow:

the bits that matter are the first input box:

$Input_1 = GUICtrlCreateInput("", 90, 480, 250, 25)

and the new input box

; Parameters

Func RemoteInfo(ByRef $Computer, ByRef $Account, ByRef $Password)

$iOk = 0

$Info = GuiCreate("Enter parameters", 200, 140, -1, -1, -1, $WS_EX_TOPMOST)

GUICtrlCreateLabel("Computer name", 5, 8, 80, 20)

$CompName = GUICtrlCreateInput($Input_1, 85, 5, 110, 20)

GUICtrlCreateLabel("Account", 5, 38, 80, 20)

$Login = GUICtrlCreateInput("administrator", 85, 35, 110, 20)

GUICtrlCreateLabel("Password", 5, 68, 80, 20)

$Passwd = GUICtrlCreateInput("", 85, 65, 110, 20, $ES_PASSWORD)

$btnOk = GUICtrlCreateButton("&Ok", 100, 100, 40, 30)

$btnCancel = GUICtrlCreateButton("&Cancel", 150, 100, 40, 30)

GuiSetState()

While 1

$msg2 = GuiGetMsg()

Select

Case $msg2 = $GUI_EVENT_CLOSE Or $msg2 = $btnCancel

ExitLoop

Case $msg2 = $btnOk

$Computer = GUICtrlRead($CompName)

$Account = GUICtrlRead($Login)

$Password = GUICtrlRead($Passwd)

$iOk = 1

ExitLoop

EndSelect

WEnd

GUISwitch($MainGui)

GuiDelete($Info)

Return $iOk

EndFunc

:) when i try to run it i get told that i havent declared the variable - am i missing something?

Thanks

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  • Moderators

Well if your using $Info1 outside the actual function, you'll probably need to Declare it Global. Also, if you are wanting the information inside of that Input, then you'll also might want to use GUICtrlRead($Input1), otherwise you'll just get the Control ID unless that's what your going for.

Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer.

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