path vs. filename

[daslick]

I have the full path of a file and I need its file name... how can I do this?

Thanks

[cppman]

Func _GetFileName($sFullPath)
    $str = StringSPlit($sFullPath, "\")
    return $str[$str[0]]
EndFunc
ProcessClose(_GetFilename(@WindowsDir&"\explorer.exe"))

Better example.

Edited October 9, 2006 by CHRIS95219

[SmOke_N]

Func _GetFileName($sFullPath)
    $str = StringSPlit($sFullPath, "\")
    return $str[$str[0]]
EndFunc
ProcessClose(_GetFilename(@WindowsDir&"\explorer.exe"))

Better example.

That's not "always" going to work, anything wrong with _PathSplit()?

[SmOke_N]

$file = StringTrimLeft($YourPath,StringInStr($YourPath,"\",0,-1))

Lar.

Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

I'll admit I didn't know that! Thanks Lar.

[daslick]

I thought of that concept, looking for the last "\" but I had no idea how to do it. There's no way I could have written that either...

Thanks!!!!!

EDIT : I only have 1 variable - $addme which is the full path to a file, what is $YourPath?

Edited October 9, 2006 by daslick

[daslick]

Ok, whatever - I just used someones code I understood. Thanks CHRIS95219. Pfff Larry

[Valik]

Did you also understand that it's probably the worst way to go about solving the problem? Larry's way isn't the best either although it's more efficient than the code you've chosen to use. Smoke's suggestion is far and away the best.

[/dev/null]

I have the full path of a file and I need its file name... how can I do this?

Thanks

.*\\(.*)

Cheers

Kurt

[Valik]

.*\\(.*)

Cheers

Kurt

*Ahem*

.*(?:\\|/)(.*)

(Not totally sure how you can use the or operator so the non-capturing group may not be necessary.)

[/dev/null]

*Ahem*

.*(?:\\|/)(.*)

(Not totally sure how you can use the or operator so the non-capturing group may not be necessary.)

$path = "C:\test\test\abc123.txt"
$pattern = ".*\\(.*)"

$file = StringRegExp($path,$pattern,1)
msgbox(0,"","Path: " & $path & " File: " & $file[0])

BTW: I did not take "/" as a valid path delimiter as all the other solutions did not as well :-) But one can easily extend the pattern to this: ".*[\\|/](.*)"

EDIT: removed first sentence as I misunderstood the post.

Cheers

Kurt

Edited October 9, 2006 by /dev/null

[cppman]

plz don't misconcept this post, im not trying to argue!

I don't understand how the code I provided would not work in a certain situation? Anyone Care to explain?

[SmOke_N]

plz don't misconcept this post, im not trying to argue!

I don't understand how the code I provided would not work in a certain situation? Anyone Care to explain?

What happens when the path name uses forward slashes?

[cppman]

ah i see. thx.