Path Environment

[stockboy]

I have an application or.exe in directory r:\or.exe

The dll's for this application are in r:\main\dk

(I can start this or.exe if I copy the dll's from r:\main\dk to r:\)

Why does it not start when I use one of those scripts?

EnvSet("PATH","%PATH%;r:\main\dk")

Run("r:\or.exe", "r:\")

or

EnvSet("PATH","r:\main\dk")

Run("r:\or.exe", "r:\")

Somebody can help me?

TNX

[lod3n]

When you use your DLL, why not include the full path? Meaning, DllCall("R:\main\dk\dllname.dll"), then you don't need the EnvSet.

[Joon]

Try this way without Path update

Run("r:\or.exe","r:\main\dk")

Edited December 7, 2006 by Joon

[stockboy]

lod3n & Joon

Thanks a lot, very useful, my 'search' is over ;o)

[MHz]

Why does it not start when I use one of those scripts?

EnvSet("PATH","%PATH%;r:\main\dk")

Run("r:\or.exe", "r:\")

FYI, To expand your path you can do it this way

$path = EnvGet("PATH")
If StringRight($path, 1) <> ";" Then
    $path &= ";"
EndIf
EnvSet("PATH",  $path & "r:\main\dk")
MsgBox(0, "", EnvGet("PATH"))

I would not use this only for one Run function as Joon's answer does it easiest.