fi3ldy Posted January 6, 2007 Share Posted January 6, 2007 ok, basically i have a file which contains information which looks like: 1|username|435m345nm435b345 Im attempting to get the "1", the very first character, except i cant just StringTrimRight because the "1" could go to 2 characters, such as "22" or "356", i basically have to cut it off and get the chracter(s) before the first | If anybody could help it would be very appriciated! this has mind boggled me Link to comment Share on other sites More sharing options...
Danny35d Posted January 6, 2007 Share Posted January 6, 2007 Look at the help file for StringSplit()Example:$Information = StringSplit('1|username|435m345nm435b345', '|')That will give you: $Information[0] = 3 $Information[1] = 1 $Information[2] = username $Information[3] = 435m345nm435b345 AutoIt Scripts:NetPrinter - Network Printer UtilityRobocopyGUI - GUI interface for M$ robocopy command line Link to comment Share on other sites More sharing options...
fi3ldy Posted January 6, 2007 Author Share Posted January 6, 2007 Look at the help file for StringSplit() Example: $Information = StringSplit('1|username|435m345nm435b345', '|') That will give you: $Information[0] = 3 $Information[1] = 1 $Information[2] = username $Information[3] = 435m345nm435b345 Thanks alot (L) Link to comment Share on other sites More sharing options...
herewasplato Posted January 6, 2007 Share Posted January 6, 2007 ...except i cant just StringTrimRight because the "1" could go to 2 characters, such as "22" or "356",...$str = "1|username|435m345nm435b345" $trimmed = StringLeft($str, StringInStr($str, "|") - 1) MsgBox(0, "", $trimmed) $str = "22|username|435m345nm435b345" $trimmed = StringLeft($str, StringInStr($str, "|") - 1) MsgBox(0, "", $trimmed) $str = "356|username|435m345nm435b345" $trimmed = StringLeft($str, StringInStr($str, "|") - 1) MsgBox(0, "", $trimmed) [size="1"][font="Arial"].[u].[/u][/font][/size] Link to comment Share on other sites More sharing options...
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