How to get the Text on Tab

[wolfbartels]

Please,

Is there a way to get the TEXT (label) on the current Tab shown of a SysTabControl32?

The function ControlCommand ( "title", "text", controlID, "CurrentTab" ) returns the number and not the lable text.

[SmOke_N]

Please,

Is there a way to get the TEXT (label) on the current Tab shown of a SysTabControl32?

The function ControlCommand ( "title", "text", controlID, "CurrentTab" ) returns the number and not the lable text.

Surprised no one has done it... Have you checked PaulIA's AU3Lib.au3 in the Examples Script forum?

If not, these may help you get you started:

http://msdn2.microsoft.com/en-us/library/ms650940.aspx

http://msdn2.microsoft.com/en-us/library/ms650986.aspx

[dabus]

What about something like

$Wintitle='Systemeigenschaften'
$Wintext='Systemleistung' ; the text that's only in the special tab

While Not StringInStr (WinGetText($Wintitle), $Wintext)
    ControlSend($Wintitle, '', '', '+^{Tab}')
WEnd

I know that's not the solution, but a workaround if the text changes within the tab - and I could bet that it does.

Edited March 19, 2007 by dabus

[wolfbartels]

What about something like

$Wintitle='Systemeigenschaften'
$Wintext='Systemleistung' ; the text that's only in the special tab

While Not StringInStr (WinGetText($Wintitle), $Wintext)
    ControlSend($Wintitle, '', '', '+^{Tab}')
WEnd

I know that's not the solution, but a workaround if the text changes within the tab - and I could bet that it does.

Thanks, it works. It is better to use

While Not StringInStr (WinGetText($Wintitle), $Wintext)=1

because $Wintext may appear somewhere else among the text. The window text always begins with the Tabs Label.

Edited March 19, 2007 by wolfbartels

[SmOke_N]

Thanks, it works. It is better to use

While Not StringInStr (WinGetText($Wintitle), $Wintext)=1

because $Wintext may appear somewhere else among the text. The window text always begins with the Tabs Label.

StringInStr() returns a boolean. There is no need to add "= 1" to it.

[wolfbartels]

StringInStr() returns a boolean. There is no need to add "= 1" to it.

Sorry, acording to HELP:

StringInStr

--------------------------------------------------------------------------------

Checks if a string contains a given substring.

StringInStr ( "string", "substring" [, casesense [, occurrence]] )

.............

Return Value

Success: Returns the position of the substring.

Failure: Returns 0 if substring not found.

that is a number, not a boolean. I checked it.

Remember: It's not what you know .... It's what you can prove!

Edited March 20, 2007 by wolfbartels