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$s = FileGetTime("pj.dll")

$t = $s[5] & $s[4] & $s[0] & $s[1] & $s[2] & $s[3]

$code1a = Log($t)

$code1b = Round($code1a)

$code1c = $code1b * 13

$code1d = Round($t / 135949)

$code1e = Hex($code1d, 6)

$code1Final = $code1c & $code1e

;cálculso com base no hd

$hd = DriveGetSerial( "c:\" )

$code2a = $hd - 111000 - $code1c

$code2b = Hex($code2a, 8)

$code2c = Log($hd)

$code2d = Round($code2c)

$code2Final = $code2b & $code2d

;password com base no arquivo

$apass1 = dec($code1e)

$apass2 = $code1b * 4

$apass3 = $apass1 & $apass2

$apass4 = $apass3 / $code1b

$apass5 = Round ($apass4)

$aFpass = Hex($apass5, 8)

;password com base no hd

$hpass1 = $code2d * 6

$hpass2 = dec($code2b)

$hpass3 = $hpass2 / $hpass1

$hpass4 = Round($hpass3)

$hpass5 = $code1b - 7

$hpass6 = $hpass4 & $hpass5

$hFpass = Hex ($hpass6, 8)

anyone can teach me what this means?

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how do i find the pass from just that o.o i need pass to runt he exe and soory fors my poor english :whistle:

Ok, you are unlikely to get any help cracking passwords if a. you don't exactly explain why you need the password and why you have the right to it, and b. you don't show what you tried yourself (so that others can redirect you where you went wrong).

Roses are FF0000, violets are 0000FF... All my base are belong to you.

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$hpass1 = $code2d * 6

$hpass2 = dec($code2b)

$hpass3 = $hpass2 / $hpass1

$hpass4 = Round($hpass3)

$hpass5 = $code1b - 7

$hpass6 = $hpass4 & $hpass5

$hFpass = Hex ($hpass6, 8)

Hex ($hpass6, 8)

please someone tell me what all this means T_T

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Hex ($hpass6, 8)

please someone tell me what all this means T_T

Help is your friend :whistle:

Hex ( expression [, length] )

Returns a string representation of an integer or of a binaryString converted to hexadecimal.

[optional] Number of characters to be returned (up to 8) for integer.

Characters are truncated from the left-hand side if length is too small.

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it is very straight forward actually..

its like a math equation..

1 + A = 2

therefore, A must = 1

so to reverse it and get that answer, you would have done this:

A = 2 - 1

Very similar process really.

Edited by tAKTelapis
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