Assigning array to array

[myt]

I'm trying to assign an array of words returned by StringSplit to another 2D array.

Here's what I did:

Dim $wordArray[8][64]

$wordArray[1] = StringSplit(...)

When I try to access something in the array like

$wordCount = $wordArray[1][0]

it gives an error about incorrect number of subscripts or dimension exceeded.

[DW1]

Did you DIM it as a 2D array?

[myt]

Did you DIM it as a 2D array?

That's what I did, didn't I?

Dim $wordArray[8][64]

[Valuater]

Maybe...

$days = StringSplit("Sun,Mon,Tue,Wed,Thu,Fri,Sat", ",")
;$days[1] contains "Sun" ... $days[7] contains "Sat"

for $x = 1 to $days[0] ; $days[0] = the total
    MsgBox(0x0, "Day", $days[$x], 2)
Next

8)

[myt]

Maybe...

$days = StringSplit("Sun,Mon,Tue,Wed,Thu,Fri,Sat", ",")
;$days[1] contains "Sun" ... $days[7] contains "Sat"

for $x = 1 to $days[0] ; $days[0] = the total
    MsgBox(0x0, "Day", $days[$x], 2)
Next

8)

I'm aware of how StringSplit works, but I'm trying to store an array of splitted strings.

For example,

$wordArray[0] would contain a list of words

$wordArray[1] would contain another list of words

and $wordArray[1][0] would be the number of words in $wordArray[1]

[SadBunny]

Poster seems to want to put an array into another array element (issue doesn't seem to be the StringSplit itself ). As far as I know, this can't be done, but maybe Val can correct me?

About the 2D array: since you dim'ed the array 2D, you need to refer to it's elements by two dimensions too.

So this will not work:

Dim $wordArray[8][64]
$wordArray[1] = "value"

... but this will work:

So this will not work:

Dim $wordArray[8][64]
$wordArray[1][2] = "value"

Now to put an array into another array element... As I said, I don't know a way to do that, but maybe Val does?

[DW1]

does an array use a special separator like the pipe "|" ? If so you would need your sub arrays to use a diff separator right?

[ChrisL]

Poster seems to want to put an array into another array element (issue doesn't seem to be the StringSplit itself ). As far as I know, this can't be done, but maybe Val can correct me?

Yes you can

#include<array.au3>

$string = "my|words|i|Want"
$string2="Some|More|words"
$aString = StringSplit($String,"|")
$aString2 = StringSplit($String2,"|")

Dim $storage[3]

$storage[1] = $aString
$Storage[2] = $aString2

For $i= 1 to Ubound($Storage) -1
    _arrayDisplay($storage[$i])
Next

[myt]

Yes you can

#include<array.au3>

$string = "my|words|i|Want"
$string2="Some|More|words"
$aString = StringSplit($String,"|")
$aString2 = StringSplit($String2,"|")

Dim $storage[3]

$storage[1] = $aString
$Storage[2] = $aString2

For $i= 1 to Ubound($Storage) -1
    _arrayDisplay($storage[$i])
Next

How would I get the number of element in $storage[1]?

I don't think I could just do $storage[1][0], because $storage is declared as a 1D array...

[SadBunny]

Yes you can

Ok! I tested something very much like your code to validate my former post... I have no idea why my attempt to to the exact same thing failed... To bad I didn't save my test code, really wondering what I did wrong. :">

Then the only remaining problem seems the '2D arrays need to be referenced in 2D' thing

[ChrisL]

How would I get the number of element in $storage[1]?

I don't think I could just do $storage[1][0], because $storage is declared as a 1D array...

I think like this

#include<array.au3>

$string = "my|words|i|Want"
$string2="Some|More|words"
$aString = StringSplit($String,"|")
$aString2 = StringSplit($String2,"|")

Dim $storage[3]

$storage[1] = $aString
$Storage[2] = $aString2


For $i= 1 to Ubound($Storage) -1
    _arrayDisplay($storage[$i])
Next

$iminterestedinthisarray=ReadArrayArray($storage[1])
Msgbox(0,"",$iminterestedinthisarray[1]);storage[1] array element 1

Func ReadArrayArray(ByRef $array)
return $array
Endfunc

[mikehunt114]

How would I get the number of element in $storage[1]?

I don't think I could just do $storage[1][0], because $storage is declared as a 1D array...

Ubound($storage[1]) will work, so long as it contains a return value from StringSplit (important because of the fact that it is of a single dimension).

Edit: typo

Edited July 18, 2007 by mikehunt114

[myt]

Ok, I've made a workaround:

I have to declare it as a 1D array , and use another temporary array.

Dim $wordArray[8]

$wordArray[1] = StringSplit(...)
$tmpArray = $wordArray[1]
$wordCount = $tmpArray[0]

I couldn't just do $wordArray[1][0] because it's now a 1D array

[SadBunny]

Ok, I've made a workaround:

I have to declare it as a 1D array , and use another temporary array.

Dim $wordArray[8]

$wordArray[1] = StringSplit(...)
$tmpArray = $wordArray[1]
$wordCount = $tmpArray[0]

I couldn't just do $wordArray[1][0] because it's now a 1D array

You can do:

$tmpArray = $wordArray[1][0]

In this case, $tmpArray would contain the 1D array stored in the 2D $wordArray[1][0]