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Security Number?


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Hey, I am very new to AutoIt, and have very little experience with it(my major is C++). Anyway though I was wanting to make a script that would login to a website for me and click a certain link(this isn't any problem so far). Where I come in trouble is at random intervals it pops up on a web page "Please enter the security number to the left"

The number is random from 1-10. And if you miss it than it changes to another number(1-10).

The numbers use the same picture and placement.

Any ideas how to code that possibly?

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Apparanetly I was wrong about it using the same pictures :). I didn't until now notice that it sometimes bolds/italics the number. Sometimes it tabs it over, sometimes it moves it up.

I had the original idea of just grabing the 10 pics. Storing them in an array. Then making a if statement inside a for loop.

As the for loop counted down if the if statement was true (ex: SecurityNumber==Pic1) then it would just fil in the correct number.

Any ideas on how I should set this up? Not wanting anyone to do it for me, just be good to know things I'll need?

Edited by Senatorwulf
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Use this

at top of code put this:

$num1= A3D3
$num2= G56F
$num3= 458K
$pic1 = $num1
$pic2 = $num2
$pic3 = $num3oÝ÷ Ù8^«zìÛaz¶!£
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That should work...

Not tested tho

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forget this bit in my last post

$RBGpic = Random(1, 3, 1)
If $RBGpic = 1 Then 
 $pic1 = GUICtrlCreatePic($pic1 , 0, 0, 604, 155) ;* change the numbers *
 GUICtrlCreateInput("", 0, 0, 604, 155) ;* change the numbers *
ElseIf $RBGpic = 2 Then 
$pic2 =  GUICtrlCreatePic($pic2 , 0, 0, 604, 155) ;* change the numbers * 
 GUICtrlCreateInput("", 0, 0, 604, 155) ;* change the numbers *
ElseIf $RBGpic = 3 Then 
 $pic3 = GUICtrlCreatePic($pic3 , 0, 0, 604, 155) ;* change the numbers *
 GUICtrlCreateInput("", 0, 0, 604, 155) ;* change the numbers *
EndIfoÝ÷ Ù©§Ü"¶aÆ®¶­sb¢b33c¶çVÓÒ4C0¢b33c¶çVÓ#ÒsSd`¢b33c¶çVÓ3ÒCS°¢b33c·3Ò·7GW&RfÆRW&P¢b33c·3#Ò·7GW&RfÆRW&P¢b33c·33Ò·7GW&RfÆRW&P¢b33c·3Òb33c¶çVÓ¢b33c·3"Òb33c¶çVÓ ¢b33c·32Òb33c¶çVÓ0

that sould work...

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