C++ return an array, how to get it using DllCall?

[laosoi]

The first C++ code:

extern "C" __declspec(dllexport) int * BioBus(void) {

int*getlo=new int[3];

getlo[0]=1000;

getlo[1]=2000;

getlo[2]=3000;

return getlo;

}

Please teach me, how to get "getlo"?

The second C++ code:

extern "C" __declspec(dllexport) const char * BioBus(void) {

const char * yo="Hello world!";

return yo;

}

Autoit code: DLLCall($dll,"str","BioBus") run OK! But:

extern "C" __declspec(dllexport) const char * BioBus(void) {

string message="Hello world!";

const char * yo=message.c_str();

return yo;

}

When i use DLLCall($dll,"str","BioBus") it return wrong string. Please tell me how to solve these problem! Thank you!

Edited August 16, 2007 by laosoi

[Bert]

[mrbond007]

I'm no dll expert but maybe this helps :

$dll_handle = DLLCall($dll,"str","BioBus")
For $i = 1 To $dll[0]
      MsgBox(0, "", $dll[$i])
Next

or

$dll_handle = DLLCall($dll,"str","BioBus")
For $i = 1 To Ubound($dll_handle) - 1
      MsgBox(0, "", $dll[$i])
Next

[laosoi]

mrbond007, as your reply:

$dll_handle = DLLCall($dll,"str","BioBus")

For $i = 1 To Ubound($dll_handle) - 1

MsgBox(0, "", $dll_handle[$i])

Next

But it returned an empty value! Anyway, thank you!

Any ideas?

[mrbond007]

mrbond007, as your reply:

$dll_handle = DLLCall($dll,"str","BioBus")

For $i = 1 To Ubound($dll_handle) - 1

MsgBox(0, "", $dll_handle[$i])

Next

But it returned an empty value! Anyway, thank you!

Any ideas?

maybe there is an error

$dll_handle = DLLCall($dll,"str","BioBus")
Msgbox(0, "", @error)

if the msgbox returns a different value than 0 than check the help file. Sorry that i can't help you more than this