Read the name of a file into a string ?

[JustDoIt]

Can someone tell me how to in AutoIt read the name of a file (not the content of the file) into a string ??? TIA.

[Kram3r]

Explain better. If you dont know the file name, where are the file ?

How do you know the file that you want to know the name ?

Dim $file
Dim $tmp

$file="test.txt"

$tmp=fileread($file)

msgbox(0,"test","This are file contents"&$tmp&" and this are the file name "&$file)

Edited September 8, 2007 by Kram3r

[JustDoIt]

Explain better. If you dont know the file name, where are the file ?

How do you know the file that you want to know the name ?

Files are created from the run of an application. File name's format is already specified inside the program but the files' names vary depending on the workload. So, I would like to check the names (of the files that are generated after the program's run) to see they are in expected format.

[JustDoIt]

Dim $file
Dim $tmp

$file="test.txt"

$tmp=fileread($file)

msgbox(0,"test","This are file contents"&$tmp&" and this are the file name "&$file)

It returns the file name as "1", while it's actually "test.txt" Edited September 8, 2007 by JustDoIt

[Kram3r]

You can use for your case:

_FileListToArray ()

Description: Lists files and\or folders in a specified path (Similar to using Dir with the /B Switch)

PS: In my environment the above example returns "test.txt" for the file name.

Edited September 8, 2007 by Kram3r

[JustDoIt]

_FileListToArray () is what I need. Thanks.

[Kram3r]

You welcome, glad to help you.