splitting a date

[stafe]

Hi,

I need to extract the day month and year from a date.

The code I have written is as follows

CODE

$myDateArray = StringSplit ($myDate, "/")

$myDay = $myDateArray[1]

$myMonth= $myDateArray[2]

$myYear= $myDateArray[3]

Is there a more elegant way to do this. I have checked out the help and thought that there may be a specific function that does this but I can not find it.

Simon

Edited September 30, 2007 by stafe

[MrCreatoR]

Hi,

It depends on the format of the date string.. show here what value is $myDate variable.

Also you might want to look at @MDAY, @MON, and @YEAR macros.

[Nahuel]

Macros:

@DAY
@MONTH
@YEARoÝ÷ Ø[§rبƮ¶­sb6æ6ÇVFRfÇC´FFRæS2fwC°¥ôæ÷r¥ôæ÷tFFR£¶WF2ââ

Is that what you wanted?

[MrCreatoR]

Macros:

Where you find those macros?

[weaponx]

stafe, your method is the easiest way to do this. In php I would do:

$date = "04/30/1973";

list($month, $day, $year) = split('[/.-]', $date);

echo "Month: $month; Day: $day; Year: $year<br />\n";

But AutoIT doesn't offer a list function.

Edited October 1, 2007 by weaponx

[HeffeD]

Where you find those macros?

Yes, they should actually be:

@MDAY and @MON.

[Tasmania]

To add my 2 cents, this is my code that I use in my programs:

$lblRstdate = GUICtrlCreateLabel("Request Date:", 8, 161, 79, 17)
$dteRstdate = GUICtrlCreateDate("", 96, 161, 105, 21, $WS_TABSTOPoÝ÷ Ù«­¢+Ù±½°ÀÌØíÑôU%
ÑɱI ÀÌØíÑIÍÑѤ)±½°ÀÌØí¹ÝÑôMÑÉ¥¹MÁ±¥Ð ÀÌØíÑ°ÅÕ½Ðì¼ÅÕ½Ðì¤()%MÑÉ¥¹1¸ ÀÌØí¹ÝÑlÉt¤±ÐìÈQ¡¸(%±½°ÀÌØíäôÅÕ½ÐìÀÅÕ½ÐìµÀìÀÌØí¹ÝÑlÉt)±Í(%±½°ÀÌØíäôÀÌØí¹ÝÑlÉt)¹%()%MÑÉ¥¹1¸ ÀÌØí¹ÝÑlÅt¤±ÐìÈQ¡¸(%±½°ÀÌØíµ½¸ôÅÕ½ÐìÀÅÕ½ÐìµÀìÀÌØí¹ÝÑlÅt)±Í(%±½°ÀÌØíµ½¸ôÀÌØí¹ÝÑlÅt)¹%()±½°ÀÌØíåÈôMÑÉ¥¹I¥¡Ð ÀÌØí¹ÝÑlÍt°È¤)±½°ÀÌØíÑôÀÌØíµ½¸µÀìÅÕ½Ðì¼ÅÕ½ÐìµÀìÀÌØíäµÀìÅÕ½Ðì¼ÅÕ½ÐìµÀìÀÌØíåÈ

That will actually take and format your date from a short-date combo box to something simliar to this:

09/01/07 or 10/12/08

Edited October 1, 2007 by Tasmania

[Nahuel]

Where you find those macros?

haha, stupid me. Sorry :">