Stripping the filename from a file path

[MadSc13ntist]

I am embarassed to post this but i hate "jerry-rig's" and "quick fixes" especially when it comes to the script i am writing... that being said, here comes the humility...

I am trying to figure out how to take a filepath (example: C:\temp\blah\blah\blah\filename.txt) and return JUST the filename (example: filename.txt)...

failed to date:

;Spliting the path into an array

$patharray = StringSplit($filepath, "\")

;and try to use $patharray[0] to tell me which array variable to grab...

$counter = $patharray[0]

$filename = $patharray[' & $counter & ']

...

but when i try

MsgBox(4096, 'test variable', 'the filename is: ' & $filename)

it returns:

the filename is: 6

(which is obviously $patharray[0]).... but no errors.... (am i close?)

it was suggested at one point that i just build a psychotically big IF THEN ELSE friggin forrest for If $counter = '1' Then..... If $counter = '2' Then....

i'm sure there has got to be a better way to do this or i'm probably just forgetting something obvious... Any help you cats could throw me would be much appreciated

[MadSc13ntist]

:: Bowing Humbly to the alter of Larry ::

I shall erect a monolithic tribute in your likeness..... one of these days...

Thanks a million Larry, i feel better about getting answers like these from people with your level of experience....

Props!

[SlimShady]

Here's my version.

Func GetFilename($Path)
   Local $TempArr
   Local $Filename
   $TempArr = StringSplit($Path, "\")
   If @error Then
      $Filename = $Path
   Else
      $Filename = $TempArr[UBound($TempArr) - 1]
   EndIf
   Return $Filename
EndFunc

[scriptkitty]

you could use it and grab the working directory by removal as well:

$fullpath="c:\temp\bobs bilfold\notes\myprogram.exe"
$filename=GetFilename($fullpath)
$path=StringReplace($fullpath,$filename,"")
msgbox(1,$filename,$path)

Func GetFilename($Path)
  Local $TempArr
  Local $Filename
  $TempArr = StringSplit($Path, "\")
  If @error Then
     $Filename = $Path
  Else
     $Filename = $TempArr[UBound($TempArr) - 1]
  EndIf
  Return $Filename
EndFunc

I personally like the StringRight and StringLeft Approach:

$path=Splitit("c:\temp\bobs bilfold\notes\myprogram.exe")
msgbox(1,$path[0],$path[1])

func SplitIt($FPath); returns Path and file in array
Dim $patharray[2]
$_loc=StringInStr($FPath,"\",0,-1)
$patharray[0]=Stringright($FPath,StringLen($FPath)-$_loc)
$patharray[1]=Stringleft($FPath,$_loc)
return $patharray
endfunc