ReFran Posted January 28, 2008 Share Posted January 28, 2008 Hi, perhaps someone can help. With stringformat("%.f", $value) I can set the decimalplaces to .xx, but how can I set a thousand separtor x,xxx.xx ? Do I have to use a for loop? Best regards, Reinhard Link to comment Share on other sites More sharing options...
PsaltyDS Posted January 28, 2008 Share Posted January 28, 2008 Hi, perhaps someone can help. With stringformat("%.f", $value) I can set the decimalplaces to .xx, but how can I set a thousand separtor x,xxx.xx ? Do I have to use a for loop? Best regards, Reinhard It's _StringAddComma:#include <string.au3> $value = 12345.67890 ConsoleWrite("Debug: " & _StringAddComma(stringformat("%.2f", $value)) & @LF) Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law Link to comment Share on other sites More sharing options...
Paulie Posted January 28, 2008 Share Posted January 28, 2008 (edited) You Can try this... #include <String.au3> $Test = 123456789.9876 $Dec = StringRegExp($Test, "\.\d*",1) $Test = StringRegExpReplace($Test,"\.\d*","") $Test=StringRegExpReplace(_StringReverse($Test), "\d{3}", "\0,") $Result=_StringReverse($Test)&$Dec[0] If StringLeft($Result,1) = "," then $Result = StringTrimLeft($Result,1) MsgBox(0,"",$Result) Edited January 28, 2008 by Paulie Link to comment Share on other sites More sharing options...
ReFran Posted January 28, 2008 Author Share Posted January 28, 2008 Great! Both works perfectly. Thanks, Reinhard Link to comment Share on other sites More sharing options...
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