odd or even

[vickerps]

How can i get autoit to know whether a number is odd or even?

[erebus]

First of all try by reading the help file.. save these forums as the last resort (as someone else has already said...)

From the Mod() function's help reference:

$n = 18
If mod($n, 2) = 0 Then
    MsgBox(0,"", $n & " is an even number.")
Else
    MsgBox(0, "", $n & " is an odd number.")
EndIf

$x = mod(4, 7);$x == 4 because the divisor > dividend

$y = mod(1, 3/4);$y == 0.25 because the divisor is a float

Edited November 30, 2004 by erebus

[the_lord_mephy]

I'm not exactly sure what Mod() does, but You could write it in your own function,

Func OddEven($num)
If StringInStr($num, ".") = 0 Then
   $lastdig = StringTrimRight($num, 1)
   If $lastdig = 1 or $lastdig = 3 or $lastdig = 5 or $lastdig = 7 or $lastdig = 9 Then
      Return 1
   EndIf
   Else
      Return 0
EndIf
EndFunc

I'm not sure what decimals are considerred lol but that should return 1 if the number is odd and 0 if the number is either even or containts a decimal =\ I didn't test but it should work

Edit:

Ah after looking at the helpfile, I know what mod does =\ That works too.

Edit2: Added EndFunc =-o

Edited December 1, 2004 by the_lord_mephy

[killaz219]

Your funcs a little messed up, you put endif instead of endfunc (or you just forgot the endfunc) to start

Also for me, it just dosnt work.

Try this and you'll see what i meen

MsgBox (0, "", Oddeven("1"))

Func OddEven($num)
If StringInStr($num, ".") = 0 Then
  $lastdig = StringTrimRight($num, 1)
  If $lastdig = 1 or $lastdig = 3 or $lastdig = 5 or $lastdig = 7 or $lastdig = 9 Then
     Return 1
  Else
     Return 0
  EndIf
EndIf
EndFunc

Edited November 30, 2004 by killaz219

[JSThePatriot]

Since that wouldnt be totally accurate as a number with a . in it isnt even you should do it as follows...

MsgBox (0, "", OddlyEven("1"))

Func OddlyEven($num)
   If Not(StringInStr($num, ".")) Then
      $lastdig = StringTrimRight($num, 1)
      If $lastdig = 1 or $lastdig = 3 or $lastdig = 5 or $lastdig = 7 or $lastdig = 9 Then
          Return 1
      Else
          Return 2
      EndIf
   ElseIf StringInStr($num, ".") Then
      Return 0
   EndIf
EndFunc

Hope this helps some,

JS

[killaz219]

JS, your script still returns the wrong number for odd values

[Matt @ MPCS]

Why would anyone write an Odd/Even function unless it used mod? erebus is entrily correct.

@the_lord_mephy - The modulus (mod()) function returns the remainder of the division of the two parameters (only real numbers accepted). In erebus's example, if you divide the number by 2 and the remainder is 0 the number is even, if the number is greater than 0 then the number is odd. This can also be used to find multiples. (e.g. 6 is a multiple of 3 because mod(6, 3) = 0)

I hope this helps clear things up a bit.

*** Matt @ MPCS

[CyberSlug]

Why would anyone write an Odd/Even function unless it used mod?

<{POST_SNAPBACK}>

Why not?

Func isEven($x)
   If $x/2 = Int($x/2) Then Return 1
EndFunc
  
;Example
For $i = 0 to 10
   If isEven($i) Then
      MsgBox(4096,"", $i & " is even")
   Else
      MsgBox(4096,"", $i & " is odd")
   EndIf
Next

Mod would be my first choice, though.

[Wolvereness]

Func wOddEven($wNum)
; -1 = ERROR, 1 = ODD, 2 = EVEN
     If $wNum = 0 OR StringInString($wNum,'.') <> 0 Then 
          Return -1
     ElseIf StringInString($wNum / 2,'.') <> 0
          Return 1
     Else
          Return 2
     EndIf
EndFunc

Edited December 1, 2004 by Wolvereness

[the_lord_mephy]

Yeah matt I realized what it did after I posted my func, you must've not seen my edit =\