send() a changing variable

[Distrophy]

I need help on how to go about coding this.

I have a list of about 25 variables that will be set, but I want to have them print out when I call a function.

$var1 = example
$var2 = example
$var3 = example
etc....
$var 25= example

Func Print()

$int = 1

While $int<26
    BeforeFunc()

    Send($var & $int)   

    AfterFunc()
    $int = $int+1
Wend
EndFunc

What my code does now is print out "example1" "example2" "example3" instead of what is actually contained within the variables.

I know there's probably an easy way to do this. Thanks for the help.

EDIT: I figured it out using an array to store the variables and then using the while to increase the value.

Edited February 7, 2008 by Distrophy

[PsaltyDS]

I need help on how to go about coding this.

I have a list of about 25 variables that will be set, but I want to have them print out when I call a function.

What my code does now is print out "example1" "example2" "example3" instead of what is actually contained within the variables.

I know there's probably an easy way to do this. Thanks for the help.

EDIT: I figured it out using an array to store the variables and then using the while to increase the value.

Arrays are the way to go, but your loop is still more complicated than you need. Use For/Next and let that increment the index for you:

Global $avVar[25] = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", _
    "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y"]

Func Print()

For $i = 0 To UBound($avVar) - 1
    BeforeFunc()
    Send($avVar[$i])
    AfterFunc()
Next

Edited February 7, 2008 by PsaltyDS

[Distrophy]

That's great. Thank you.