Creating a dynamic number of loops

[fielmann]

Hello autoit friends,

howto create a dynamic number of loops?

It should like like (e.g. for a number of 3 loops):

;~~~~~~~~~~~~~~~~~~

For $loop1 = 1 to 10

For $loop2 = 1 to 10

For $loop3 = 1 to 10

; do something

next

next

next

;~~~~~~~~~~~~~~~~~~

But how to make it DYNAMIC ?

Any ideas?

Carsten

Edited March 5, 2008 by fielmann

[Xand3r]

is this what you want?

$min=Random(1,10,1)
$max=Random(10,100,1)

For $i=$min to $max
;do stuff
Next

if not then try to explain better what you want..

Edited March 5, 2008 by alexmadman

[martin]

Hello autoit friends,

howto create a dynamic number of loops?

It should like like (e.g. for a number of 3 loops):

;~~~~~~~~~~~~~~~~~~

For $loop1 = 1 to 10

For $loop2 = 1 to 10

For $loop3 = 1 to 10

; do something

next

next

next

;~~~~~~~~~~~~~~~~~~

But how to make it DYNAMIC ?

Any ideas?

Carsten

You need some sort of recursive function. Here is a simple example

Dim $a[4] = [3,4,5,2];the upper count for each loop
Dim $r[4]
Global $x=0
startloop($a,0)

Func startloop($b,$c)
Local $n
If $c < UBound($b) Then
        For $n = 1 To $b[$c]
            $r[$c] = $n
            Startloop($b,$c + 1)
        Next
    Else
        Dosomething()
    EndIf
EndFunc
Func Dosomething()
    $x += 1
    ConsoleWrite("loop vals are ")
    For $p = 1 To UBound($a)
      ConsoleWrite($r[$p - 1] & ', ')
    Next
    ConsoleWrite( "count = " & $x & @CRLF)
EndFunc

BTW, welcome to the forums; an interesting first question.

EDIT: improved example a bit

Edited March 5, 2008 by martin

[fielmann]

You need some sort of recursive function. Here is a simple example

[...]

BTW, welcome to the forums; an interesting first question.

EDIT: improved example a bit

Hello Martin!

thx 4 reply an the example with the recursive function.

that was exactly what I'm seraching for

thx also 4 your pleasent welcome!

I work several years with autoit 2 + 3, but I never realized this forum.