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TimerDiff() Need to display in seconds


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I was thinking StringFormat() or StringTrimLeft() but, StringTrimLeft() Wouldn't be accurate, if you took more than 99 seconds. I just need to display the seconds, and 2 digits after it. So it shows like this:

$Time = TimerInit()
Sleep(15000)
MsgBox(0, "", TimerDiff($Time))

And, I need that to display 15.00 :)

If anyone could help with this topic, thanks. I wish I could learn StringFormat() It's complicated though.

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You won't here's a perfectly good example without it:

$timer=TimerInit()
Sleep(15000)
$seconds=Round(TimerDiff($timer)/1000,2)
If IsInt($seconds) Then $seconds&=".00"
MsgBox(0,"",$seconds)oÝ÷ Ù(¦¦W×}ç-÷¿ªê-y&¦zØbî¶W­¶)àJÚâh®f­va{
+«­¢+ØÀÌØíÑ¥µÈõQ¥µÉ%¹¥Ð ¤)M±À ÄÔÀÀÀ¤(ÀÌØíͽ¹ÌôMÑÉ¥¹½ÉµÐ ÅÕ½Ðì¸ÉÅÕ½Ðì°Q¥µÉ¥ ÀÌØíÑ¥µÈ¤¼ÄÀÀÀ¤)5Í ½à À°ÅÕ½ÐìÅÕ½Ðì°ÀÌØíͽ¹Ì¤

:)

Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law
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