help with some math

[AustrianOak]

i need some help with a bit of math for a sec..

If Round(Int(TimerDiff($aTimer_Inits[1])) / 5000 / 60 , 2) >= $nTrial Then $nDays_Over += 5

that line basically means if 5 minutes has gone by then set $nDays_Over to 5

5000/60 is 5 minutes i know that for sure....

but what is 5 days?

just 5000 maybe?

[martin]

i need some help with a bit of math for a sec..

If Round(Int(TimerDiff($aTimer_Inits[1])) / 5000 / 60 , 2) >= $nTrial Then $nDays_Over += 5

that line basically means if 5 minutes has gone by then set $nDays_Over to 5

5000/60 is 5 minutes i know that for sure....

but what is 5 days?

just 5000 maybe?

I expect you would be better off using date functions if yu want to deal with days. Have a look at Date.au3 in the includes.

1000ms is 1 second, so 5 seconds is 5000mS as you say. 5 days is 1000*60*60*24*5.

(1000ms/sec)*(60sec/min)*(60min/hr)*(24hr/day)*5day

[AustrianOak]

so since this is 5 minutes

If Round(Int(TimerDiff($aTimer_Inits[1])) / 5000 / 60 , 2) >= $nTrial Then $nDays_Over += 5

i would change it to look like this so it would be 5 days?

If Round(Int(TimerDiff($aTimer_Inits[1])) * 1000 * 60 * 60 * 24 * 5 , 2) >= $nTrial Then $nDays_Over += 5

did i do everything correct?