hex

[UPSman2]

ok so maybe im having a dumb day, but why when i execute this script it returns 03A5FF18 instead of 3A60000, why?

$div = 0x3A60000 / 0xDF8
$a1 = "0x" & Hex($div)
$a2 = $a1 * 0xDF8
MsgBox(0,"",Hex($a2))

[TheCreator]

What I do with something like this is just walk thrhough the code.

$div = 0x3A60000 / 0xDF8

You're dividing hex. try this on a calculator, and see if it's what you expect.

$a1 = "0x" & Hex($div)

don't think you need the 0x there.

$a2 = $a1 * 0xDF8

You multiply it by what you divided.

MsgBox(0,"",Hex($a2))

$a2 is already hex. your converting what you have, to hex again

[UPSman2]

autoit returns hex equations in decimal format, and yes i do need the "0x"

thx for reply though

Edited April 9, 2008 by UPSman2

[UPSman2]

sorry for double post, but i think its just hex doesnt carry decimals and just rounds... thus my equation is wrong *cry*... o well

[Richard Robertson]

Hexadecimal is used for integers most commonly. I don't know how you'd represent a floating point number in hex.